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There is apporximately 0.07 mol of He in .268g, which is approximately 4.21x10^-23 atoms.
1.3 mol
48,177 134 32.1023 atoms
0.63 mol of (NH4)2SO4 contain 3,978.10e23 hydrogen atoms.
16.0 lbs = 7,257 g of O2 Oxygen exists in the gas form as 02 7,257g O2 * 1 mol O2/ 32 g * 2 mol O / 1 mol O2 * 6.022x10^23 atoms/mol = 2.73E26 atoms of O
There is apporximately 0.07 mol of He in .268g, which is approximately 4.21x10^-23 atoms.
18 mol of NH3 (ammonia) contains 18 mol of N atoms. 1 mole of N2 (nitrogen gas) contains 2 mol N atoms. so 9 mol N2 is used to produce 18 mol NH3.
the constant Mole (mol): 6.02 x 10^23 are how many atoms you have per mol so the answer can be 7 mol atoms or 6.02 x 10^23 atoms per mol x 7 actual answer is 4.214 X10^24 atoms in 7 mol
A mol = 6,022x10^23 atoms 1,5 mol = 9,033x10^23 atoms Always.
there are 6 molecules of chlorine gas
There are 1.204 x 1023 atoms in .200 mol of Pb.
There are 1.41 e24 atoms of Na in 2.35 mol of NaCl.
0.45 mol BaSO4 have 2,698.10e23 sulfur atoms.
1.3 mol
The answer is 18,061.1023 atoms.
481,7713432.1023 atoms
48,177 134 32.1023 atoms