The formula mass of KMnO4 is 158.0
Amount of KMnO4 = mass of sample / molar mass = 100/158.0 = 0.633 mol
There are 0.633 moles in 100g of potassium permanganate.
No of moles = wt (in g) / mol wt
and molecular weight of KMnO4 = (39) + (55) + (4 x 16) = 158
Hence, No of moles = 100/158 = 0.632
There are 3 different types of elements in KMn04.
The number of atoms is 12,044.10e23.
0.63 round to the nearest hundret
2 mols of O2
0.02M
158
?
Molarity = moles of solute/Liters of solution ( 75.0 ml = 0.075 Liters ) Algebraically manipulate, moles of solute = Liters of solution * Molarity Moles KMnO4 = (0.075 Liters)(0.0950 M) = 7.13 X 10 -3 moles KMnO4 ------------------------------------
The formula for potassium permanganate is KMnO4
Formula: KMnO4
Number of moles= Mass/molar mass (g/mol) Hence Mass= mol × molar mass Mol=2.55 Molar mass of KMnO4= 39+55+(16×4)= 158g/mol Where K=39, Mn=55 and O =16 Hence Mass of KMnO4 in 2.55 mols of the compound= 2.55×158= 402.9g.
KMnO4 will react with compounds having unsaturation (double bond or triple bond). Since alkenes have double bond, it will react with KMnO4 and decolourize dilute KMnO4 solution.
The molar mass of KMnO4 is 158,3415 g.The molarity of this solution is 0,1 M.
Molarity = moles of solute/Liters of solution ( 75.0 ml = 0.075 Liters ) Algebraically manipulate, moles of solute = Liters of solution * Molarity Moles KMnO4 = (0.075 Liters)(0.0950 M) = 7.13 X 10 -3 moles KMnO4 ------------------------------------
The formula for potassium permanganate is KMnO4
acidicness number of kmno4
KMnO4.
The compound potassium permanganate has chemical formula KMnO4 Molecular mass of KMnO4 = 39.1 + 54.9 + 4(16.0) = 158.0 Mass of KMnO4 = amount of KMnO4 x Molecular mass of KMnO4 = 2.55 x 158.0 = 403g
Potassium Hydroxide is KOH and potassium permanganate is KMnO4.
tell me about the vlance of Mn in KMnO4
Formula: KMnO4
Number of moles= Mass/molar mass (g/mol) Hence Mass= mol × molar mass Mol=2.55 Molar mass of KMnO4= 39+55+(16×4)= 158g/mol Where K=39, Mn=55 and O =16 Hence Mass of KMnO4 in 2.55 mols of the compound= 2.55×158= 402.9g.
KMnO4 will react with compounds having unsaturation (double bond or triple bond). Since alkenes have double bond, it will react with KMnO4 and decolourize dilute KMnO4 solution.
Equivalent weight of KMnO4 is equal with molar weight of KMnO4. The some is and for K2MnO4, K2MnO4 - e +OH- --------- KMnO4 + KOH In general, Equivalent weight = Molar weight / Number of electrons that take or give one molecule Equivalent weight of KMnO4 = Molar weight of KMnO4 / 1