The formula mass of KMnO4 is 158.0
Amount of KMnO4 = mass of sample / molar mass = 100/158.0 = 0.633 mol
There are 0.633 moles in 100g of potassium permanganate.
Molarity = moles of solute/Liters of solution ( 75.0 ml = 0.075 Liters ) Algebraically manipulate, moles of solute = Liters of solution * Molarity Moles KMnO4 = (0.075 Liters)(0.0950 M) = 7.13 X 10 -3 moles KMnO4 ------------------------------------
(158 g = 1 mole) --- molar mass of potassium permanganate. You also need to specify the volume to be made. For 1 liter just add 15.8 g in a volumetric flask to make 1000 ml (1 liter) of solution.
To find the volume of 0.24M Na2SO4 oxidized by 0.32 kmno4, first calculate the number of moles of KMnO4 using the formula M1V1 = M2V2. Then, use the mole ratio between KMnO4 and Na2SO4 (from the balanced equation) to find the moles of Na2SO4 oxidized. Finally, convert the moles of Na2SO4 to volume using its molarity.
The formula for potassium permanganate is KMnO4
Since Normality (N) is a measure of the number of equivalents of a substance in a solution, and molarity is a measure of the concentration of a substance in a solution, to convert from Normality to Molarity for sodium bicarbonate (NaHCO3), you would need to divide the Normality by the total acidity or basicity of the compound. Since sodium bicarbonate has one replaceable hydrogen atom (H), the molarity is equal to the Normality for this compound. Thus, the molarity of a 0.2 Normal sodium bicarbonate solution is 0.2 M.
The molar mass of KMnO4 is 158,3415 g.The molarity of this solution is 0,1 M.
To find the mass of KMnO4 needed, you can use the formula: mass = molarity x volume x molar mass. First, calculate the moles of KMnO4 using moles = molarity x volume. Then, multiply the moles by the molar mass of KMnO4 to find the mass needed.
Molarity = moles of solute/Liters of solution ( 75.0 ml = 0.075 Liters ) Algebraically manipulate, moles of solute = Liters of solution * Molarity Moles KMnO4 = (0.075 Liters)(0.0950 M) = 7.13 X 10 -3 moles KMnO4 ------------------------------------
(158 g = 1 mole) --- molar mass of potassium permanganate. You also need to specify the volume to be made. For 1 liter just add 15.8 g in a volumetric flask to make 1000 ml (1 liter) of solution.
To find the volume of 0.24M Na2SO4 oxidized by 0.32 kmno4, first calculate the number of moles of KMnO4 using the formula M1V1 = M2V2. Then, use the mole ratio between KMnO4 and Na2SO4 (from the balanced equation) to find the moles of Na2SO4 oxidized. Finally, convert the moles of Na2SO4 to volume using its molarity.
The formula for potassium permanganate is KMnO4
To determine the volume of 0.100 M KMnO4 required to titrate 0.33 g of K2Cu(C2O4)·2H2O, first calculate the moles of K2Cu(C2O4)·2H2O. The molar mass of K2Cu(C2O4)·2H2O is approximately 197.12 g/mol, so 0.33 g corresponds to about 0.00167 moles. The reaction between KMnO4 and K2Cu(C2O4) typically involves a 1:1 stoichiometry, which means you would need 0.00167 moles of KMnO4. Using the molarity of KMnO4 (0.100 M), the volume required would be approximately 16.7 mL (calculated using the formula: Volume = Moles / Molarity).
Benzene does not react directly with potassium permanganate (KMnO4) under normal conditions. Benzene is a stable aromatic compound and does not undergo typical alkene or alkane reactions with oxidizing agents like KMnO4.
acidicness number of kmno4
KMnO4.
tell me about the vlance of Mn in KMnO4
Since Normality (N) is a measure of the number of equivalents of a substance in a solution, and molarity is a measure of the concentration of a substance in a solution, to convert from Normality to Molarity for sodium bicarbonate (NaHCO3), you would need to divide the Normality by the total acidity or basicity of the compound. Since sodium bicarbonate has one replaceable hydrogen atom (H), the molarity is equal to the Normality for this compound. Thus, the molarity of a 0.2 Normal sodium bicarbonate solution is 0.2 M.