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(158 g = 1 mole) --- molar mass of potassium permanganate.
You also need to specify the volume to be made. For 1 liter just add 15.8 g in a volumetric flask to make 1000 ml (1 liter) of solution.
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∙ 11y ago
To calculate the amount of KMnO4 in grams required for a 0.1N solution, you need to know the molecular weight of KMnO4, which is about 158.034 g/mol. For a 0.1N solution, the molarity is 0.1 mol/L. Using the formula: grams = molarity (mol/L) * molecular weight (g/mol) * volume (L), you can determine the grams of KMnO4 needed for a specific volume.
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You have .2 n kmno4 which you have to dilute it to 0.05n kmno4 how can you dilute that?
To dilute 0.2N KMnO4 to 0.05N KMnO4, you can add 4 times the volume of water to the original volume of KMnO4 solution. For example, if you have 100 mL of 0.2N KMnO4, you would add 400 mL of water to achieve a 0.05N KMnO4 solution. Mix thoroughly to ensure uniform dilution.
How do you make 10 percent solution from 20 percent solution?
To make a 10% solution from a 20% solution, you can mix equal volumes of the 20% solution with water. For example, to make 1 liter of 10% solution, mix 500 ml of the 20% solution with 500 ml of water.
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You have .2 n kmno4 which you have to dilute it to 0.05n kmno4 how can you dilute that?
To dilute 0.2N KMnO4 to 0.05N KMnO4, you can add 4 times the volume of water to the original volume of KMnO4 solution. For example, if you have 100 mL of 0.2N KMnO4, you would add 400 mL of water to achieve a 0.05N KMnO4 solution. Mix thoroughly to ensure uniform dilution.
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How many grams of IKI would it take to obtain a 100mL solution of 0.300 M IKI?
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How many grams of calcium chloride would you add to water for a totoal volume of 500 ml to make a 5 percent solution?
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How many grams of potassium permanganate contains 27.5 grams of oxygen?
The molar mass of potassium permanganate (KMnO4) is 158.03 g/mol. Each molecule contains 4 oxygen atoms. Using stoichiometry, you can calculate that 27.5 grams of oxygen corresponds to approximately 56.25 grams of potassium permanganate.
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If your solution is a total of 414g and 3.06% of it needs to be NaCl, then you just take 414 x .0306 = grams of NaCl. The rest of the grams will be from other species in the solution.
In manufacture of potassium permanganate by electrolysis of k2mno4 what should be the equivalent weight of kmno4 how much kmno4 will be produced by 96478 coulombs or one farady?
The equivalent weight of K2MnO4 is 158 g/mol. To calculate the produced KmnO4, we first determine the number of faradays in 96478 coulombs (1 F = 96485 C). Then we use the stoichiometry: 1 mol of K2MnO4 produces 1 mol of KMnO4. So, 158 g of K2MnO4 will produce 158 g of KMnO4.
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