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(158 g = 1 mole) --- molar mass of potassium permanganate.

You also need to specify the volume to be made. For 1 liter just add 15.8 g in a volumetric flask to make 1000 ml (1 liter) of solution.

Q: How many grams KMnO4 take in 0.1N KMnO4 solution?

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To dilute 0.2N KMnO4 to 0.05N KMnO4, you can add 4 times the volume of water to the original volume of KMnO4 solution. For example, if you have 100 mL of 0.2N KMnO4, you would add 400 mL of water to achieve a 0.05N KMnO4 solution. Mix thoroughly to ensure uniform dilution.

To make a 10% solution from a 20% solution, you can mix equal volumes of the 20% solution with water. For example, to make 1 liter of 10% solution, mix 500 ml of the 20% solution with 500 ml of water.

The answer is 9.6 grams.

take 0.25 grams of sodium hypochlorite and dissolve it into 100 mls of water, put in a pH probe and add boric acid until the pH is about 8.0, which takes about 0.65 grams of boric acid

It takes about 28.35 grams of gold to make one ounce.

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To dilute 0.2N KMnO4 to 0.05N KMnO4, you can add 4 times the volume of water to the original volume of KMnO4 solution. For example, if you have 100 mL of 0.2N KMnO4, you would add 400 mL of water to achieve a 0.05N KMnO4 solution. Mix thoroughly to ensure uniform dilution.

Take 5 grams of calcium chloride and dissolve it in 100ml of solution to get a 5% solution of calcium chloride. The standard way to make a weight-volume solution is to take grams of the dry substance in 100ml of volume.

It would be 12.6g of IKI to obtain the 100mL solution of 0.300 M IKI.

It would be 12.6g of IKI to obtain the 100mL solution of 0.300 M IKI.

It depends how strong a solution you want to make. The molecular mass of NaCl is 58.44, so for a 1 molar solution you would dissolve 58.44 grams in water and make the volume up to 1 litre. For a 0.1 mol solution you'd take 5.844g to a litre, and a 2 mol solution you'd take 116.88g to a litre of water.

Equivalent weight of KMnO4 is equal with molar weight of KMnO4. The some is and for K2MnO4, K2MnO4 - e +OH- --------- KMnO4 + KOH In general, Equivalent weight = Molar weight / Number of electrons that take or give one molecule Equivalent weight of KMnO4 = Molar weight of KMnO4 / 1

This is more of a math question that requires a bit of knowledge of chemistry. So it helps to know the steps of this answer mathematically. Additionally it's worth noting that there are a number of ways to answer this question. The method I provide may take an extra step, but it allows for a better understanding of the process.First we need to know some basic information about potassium permanganate, KMnO4. This basic information can be found on a periodic table, like the one in the link below. The first step is finding the weight of oxygen in one mole of potassium permanganate as a percent. For this you need to know the atomic weights of the elements involved.K: 39.1 gramsMn: 54.9 gramsO: 16.0 grams Ã— 4 atoms = 64.0 gramsKMnO4: 39.1 + 54.9 + 64.0 = 158.0 grams/molSo now we know the weight of one mole of potassium permanganate (158.0 grams). Because we also know the weight of oxygen, we can find the percent of oxygen in the compound by mass.64.0 grams O Ã· 158.0 grams KMnO4 = 0.405 = 40.5%In one mole of potassium permanganate, 64.0 grams of it is oxygen, meaning 40.5% of it is oxygen. Because of the Law of Definite Proportions, we know that in any amount of potassium permanganate, 40.5% of it is oxygen.Then you can set up an equation.40.5% of (some amount of KMnO4) = 27.5 grams oxygenLet's set the amount of KMnO4 as the variable "x".0.405x = 27.5x = 67.9 grams KMnO4

If your solution is a total of 414g and 3.06% of it needs to be NaCl, then you just take 414 x .0306 = grams of NaCl. The rest of the grams will be from other species in the solution.

The needed mass of sodium chloride is 29,22 g.

Just take 3 grams and add this to 1000 litres (= 1,000 kg = 1,000,000 (million) grams)

To make a 10% solution from a 20% solution, you can mix equal volumes of the 20% solution with water. For example, to make 1 liter of 10% solution, mix 500 ml of the 20% solution with 500 ml of water.

1 kg