2 AD
ac + 2ad + 2bc + 4bd = a(c + 2d) + 2b(c + 2d) = (a + 2b)(c + 2d) Now expand to confirm your answer: c(a + 2b) + 2d(a + 2b) = ac + 2bc + 2ad + 4bd ≡ ac + 2ad + 2bc + 4bd
ac + 2ad + 2bc + 4bd (ac + 2ad) + (2bc + 4bd) group the figures a(c + 2d) + 2b(c + 2d) remove the common divisors of each set (a + 2b)(c + 2d) take the figures in parentheses as one set, and add the outside figures as the other
vf2 = vi2 + 2ad, where vf is final velocity, vi is initial velocity, a is acceleration, and d is displacement. Solve for a. vf2 = vi2 + 2ad vf2 - vi2 = 2ad (vf2 - vi2)/2d = a
(2a + b)(2c + d)
Ptolemy created the Geocentric model in 2AD
vf=vi+at or vf2=vi2+2ad where a=-9.8m/s2
4ac + 2ad + 2bc +bd = 2a*(2c + d) + b*(2c + d) = (2c + d)*(2a + b)
The equation that does involve time is.. v² = v₀² + 2ad
0 men. 2AD no longer exists. It cased it's colors back in 1995.
acceleration cannot be calculated from these values alone unless one makes a few assumptions: Vf=final velocity Vi=initial velocity a=acceleration d=displacement t=time assume Vi=0 (Vf-Vi)/t=a Vf=at+Vi Vf**2=Vi**2+2ad (at)**2=2ad aatt=2ad att=2d a=2d/t**2
(2a + b)(2c + d)