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The atomic number of iodine, or I, is 53. Thus, neutral iodine would have 53 protons and 53 electrons. However, since we're talking about I-, we need to add an additional electron to this number, making it 54. Finally, the specific isotope of iodine in question, 131I, has 131 - 53 = 78 neutrons.

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Q: How many protons neutrons and electrons are in an iodide 131 ion with a negative charge?
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