Let the number of rabbits be ( r ) and the number of chickens be ( c ). The total number of heads gives us the equation ( r + c = 35 ), and the total number of legs gives us ( 4r + 2c = 94 ). Solving these equations, we find that there are 23 chickens and 12 rabbits.
12 chickens 4 rabbits
7 cows and 11 chickens. Cows have 4 legs. Chickens have 2 legs. (4 legs)(7 cows) + (2 legs)(11 chickens) = 50 legs. 7 cow heads = 11 chicken heads = 18 heads.
On a farm there are chickens and three-legged-cows. There are total of 49 heads and 130 legs. How many chickens are on the farm?
I believe it's 75 rabbits. There are 105 animals. There are 75 x 4(rabbit legs) = 300 legs and 30 x 2(chicken legs) = 60 legs, which totals 360 legs. The 75 rabbits plus 30 chickens equals 105 animals.
There are 5n chickens and 20-3n rabbits, for n = 1,2,3,4,5 or 6.
85 chickens
Suppose there are x chickens and y cows Then heads => x + y = 64 And Legs => 2x + 3y = 147 2*Heads: 2x +2y = 128 Subtract from Legs: 19 = y Substitute in Heads: x = 45 Answer: 45 chickens.
There are 42 chickens in the farm.
there are 36 horses and 23 chickens.........
Let's denote the number of chickens as C and the number of rabbits as R. We can write two equations based on the given information: C + R = 72 (total number of heads) and 2C + 4R = 200 (total number of feet). Solving these equations simultaneously, we find there are 50 chickens and 22 rabbits in the cage.
35 pigs, 65 chickens
48 chickens 1 pig