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There are 1,45/237 = 0,00612 moles of the compound. Multiplying this amount of substance with Avogadro's number gives us the number of residing molecules:

0,00612 x 6,022*1023 = 3,68*1021 particles.

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Q: How many representative particles are in 1.45 g of a molecular compound with a molar mass of 237g?
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Related questions

How many representative particles are in 1.45 g of a molecular compound with a molar mass of 237 g?

1.45 g of a molecular compound with a molar mass of 237 represents 1.45/237 or 6.118 X 10-3 mole. Assuming that "representative particles" in the question means "molecules", this is (6.118 X 10-3){Avogadro's Number} or 3.68 X 1021 molecules.


How many representative particles are in 1.45 g of a molecular compound with a mass of 237 g?

1.45 g of a molecular compound with a molar mass of 237 represents 1.45/237 or 6.118 X 10-3 mole. Assuming that "representative particles" in the question means "molecules", this is (6.118 X 10-3){Avogadro's Number} or 3.68 X 1021 molecules.


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