1.45 g of a molecular compound with a molar mass of 237 represents 1.45/237 or 6.118 X 10-3 mole. Assuming that "representative particles" in the question means "molecules", this is (6.118 X 10-3){Avogadro's Number} or 3.68 X 1021 molecules.
c3h6-apex
A sample of a compound contain 1.52 g of Nitrogen and 3.47 g of Oxygen. The molar mass of this compound is between 90 grams and 95 grams. The molecular formula and the accurate molar mass would be N14O35.
c12h24
molecular formula
The molecular mass of a compound with the formula CH2O is approx. 30, not 120.
1.45 g of a molecular compound with a molar mass of 237 represents 1.45/237 or 6.118 X 10-3 mole. Assuming that "representative particles" in the question means "molecules", this is (6.118 X 10-3){Avogadro's Number} or 3.68 X 1021 molecules.
There are 1,45/237 = 0,00612 moles of the compound. Multiplying this amount of substance with Avogadro's number gives us the number of residing molecules: 0,00612 x 6,022*1023 = 3,68*1021 particles.
The molecular formula of a compound can not be determined solely based on its molar mass. In this case, without additional information, it is not possible to determine the molecular formula of the compound CH2.
4.51 g x 1 mol x 6.022 x 1023 molecules = 9.95 x 1021 molecules .............273 g ............... 1 mol
avagadros number
C12h24
C6h12o6
In most cases one cannot identify a compound by its molar mass. There are too many possibillities.
C3H6
c3h6-apex
c12h24
c3h6