You in a cult ? ...
This question is suss -_-
Barium sulfate (BaSO₄) is known for its very low solubility in water, with a solubility product (Ksp) indicating that only about 0.0002 grams can dissolve in 1 liter of water at room temperature. Therefore, to dissolve 1 gram of barium sulfate, an impractically large volume of water—approximately 5,000 liters—would be needed. This highlights the compound's nature as a sparingly soluble salt.
39.25 liters.
That depends on the model of the transformer. I have seen transformers that required 7500 liters and some that needed 2,5 liters.
Required for what? Required to do what? Required by whom? Required by what authority? What are you trying to figure out? This could be a drinking water quality question for the municipal water authority, or a chemistry question [how much can you dissolve], or a whole number of other possibilities. Also, so you mean Magnesium metal [Mg] or Magnesium Chloride [MgCl2]? To go along with the Potassium Chloride [KCl].
To calculate the liters of water needed, first convert 1 gram of calcium phosphate into moles. Then, use the molar mass of calcium phosphate to convert moles into grams. Next, apply the solubility value to calculate the amount of calcium phosphate that can dissolve in 1 liter of water. This will give you the approximate amount of water needed to dissolve 1 gram of calcium phosphate.
More information is required to answer this question. 3.5 what?
2
240
26.8125 g
1 litre = 1000 millilitres. You now have all the information required to answer this and similar questions.
At standard temperature and pressure (STP), one mole of any ideal gas occupies 22.4 liters. To find the number of moles of ammonia gas (NH₃) required to fill a volume of 50 liters, you can use the formula: moles = volume (liters) / volume per mole (liters/mole). Therefore, the calculation is 50 liters / 22.4 liters/mole = approximately 2.24 moles of NH₃ are needed.
150 Ltr.........