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Barium sulfate (BaSO₄) is known for its very low solubility in water, with a solubility product (Ksp) indicating that only about 0.0002 grams can dissolve in 1 liter of water at room temperature. Therefore, to dissolve 1 gram of barium sulfate, an impractically large volume of water—approximately 5,000 liters—would be needed. This highlights the compound's nature as a sparingly soluble salt.
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Barium hydroxide contained 2.74g in 100cm of water titration of 20cm required 18.7cm of a hydrochloric acid solution for complete neutralization what is the molarity of the barium hydroxide?
To find the molarity of the barium hydroxide solution, first calculate the number of moles of hydrochloric acid used in the titration. Then use the stoichiometry of the reaction to determine the number of moles of barium hydroxide present. Finally, divide the moles of barium hydroxide by the volume of the solution in liters to get the molarity.
How many grams of zebulose would you have to dissolve in 4 liters of water to make a 250 millimolar solution?
26.8125 g
How many moles of ammonia gas NH3 are required to fill a volume of 50 liters at STP?
At standard temperature and pressure (STP), one mole of any ideal gas occupies 22.4 liters. To find the number of moles of ammonia gas (NH₃) required to fill a volume of 50 liters, you can use the formula: moles = volume (liters) / volume per mole (liters/mole). Therefore, the calculation is 50 liters / 22.4 liters/mole = approximately 2.24 moles of NH₃ are needed.
What does 5.3 liters equal in ml?
1 litre = 1000 millilitres. You now have all the information required to work out, for yourself, the answer to this and similar questions.
What is the minimum required blood flow in relation to the human body?
For an awake 70 kg male, it's about 5 liters per min. If you're asleep it can fall to about 4 liters per min.
How many grams of solid barium sulfate form when 22.6 mL of 0.160 M barium chloride reacts with 54.6 mL of 0.055 M sodium sulfate?
Balanced equation first. BaCl2 + Na2SO4 -> 2NaCl + BaSO4 22.6 ml BaCl2 = 0.0226 liters 54.6 ml Na2SO4 = 0.0546 liters 0.160 M BaCl2 = moles BaCl2/0.0226 liters = 0.00362 moles BaCl2 0.055 M Na2SO4 = moles Na2SO4/0.0546 liters = 0.0030 moles Na2SO4 The ratio of BaCl2 to Na2SO4 is one to one, so either mole count wull drive this reaction. Use 0.0003 moles Na2SO4 0.0030 moles Na2SO4 (1 mole BaSO4/1 mole Na2SO4)(233.37 grams/1 mole BaSO4) = 0.700 grams of BaCO4 produced
How many grams of sodium sulfate are required to prepare a 350 mL solution whose concentration is 0.683 M?
Amount of sodium sulfate required = 0.683 x 350/100 = 0.239The formula mass of sodium sulfate, Na2SO4 is 2(23.0) + 32.1 + 4(16.0) = 142.1 Therefore mass of sodium sulfate required = 0.239 x 142.1 = 34.0g Approximately 34 grams of sodium sulfate would be needed.
How many moles of copper sulfate are needed to make 2.50 Liters of 0.125 moles solution?
0.125 Molar solution! Molarity = moles of solute/Liters of solution Algebraically manipulated, Moles of copper sulfate = 2.50 Liters * 0.125 M = 0.313 moles copper sulfate needed ===========================
Barium hydroxide contained 2.74g in 100cm of water titration of 20cm required 18.7cm of a hydrochloric acid solution for complete neutralization what is the molarity of the barium hydroxide?
To find the molarity of the barium hydroxide solution, first calculate the number of moles of hydrochloric acid used in the titration. Then use the stoichiometry of the reaction to determine the number of moles of barium hydroxide present. Finally, divide the moles of barium hydroxide by the volume of the solution in liters to get the molarity.
How many sleeping pills are required to dissolve in 15 liters of water which should at least cause 4 hours of deep sleep to 8 persons?
You in a cult ? ... This question is suss -_-
Calculate the molarity of a solution that contains 35.0g of barium chloride dissolved in 450.0ml solution?
First, calculate the number of moles of barium chloride using its molar mass. Then, convert the volume from milliliters to liters. Finally, divide the number of moles by the volume in liters to find the molarity of the solution.
What mass of ammonium sulphate is required to produce 0.5 liters of mole solution?
To determine the mass of ammonium sulfate needed to make a 0.5 M solution: Calculate the molar mass of ammonium sulfate (NH4)2SO4. Use the formula: Mass (g) = Molarity (M) x Volume (L) x Molar mass (g/mol). Plug in the values: Molarity = 0.5 M, Volume = 0.5 L, and Molar mass of (NH4)2SO4. Calculate to find the mass of ammonium sulfate required.
How many liters required for 280 miles at 27 miles to the gallon?
39.25 liters.
How much oil in liters required for sealed type 95 KV 1200mA - TR Set transformer?
That depends on the model of the transformer. I have seen transformers that required 7500 liters and some that needed 2,5 liters.
What is a procedure for making 100 ml of a 0.10 M solution of barium nitrate?
Ba(NO3)2 Molarity = moles of solute/Liters of solution ( 100 ml = 0.100 liters ) 0.10 M Ba(NO3)2 = moles Ba(NO3)2/0.100 liters = 0.01 moles Ba(NO3)2 (261.32 grams/1 mole Ba(NO3)2) = 2.6 grams of Ba(NO3)2 needs to be put into that 100 milliliters of solution.
How many kilos of Magnesium and Potassium Chloride required in 21000 liters of water?
Required for what? Required to do what? Required by whom? Required by what authority? What are you trying to figure out? This could be a drinking water quality question for the municipal water authority, or a chemistry question [how much can you dissolve], or a whole number of other possibilities. Also, so you mean Magnesium metal [Mg] or Magnesium Chloride [MgCl2]? To go along with the Potassium Chloride [KCl].
Molarity of 734 grams of lithium sulfate are dissolved to make 2500ml of solution?
To find the molarity of the solution, first calculate the number of moles of lithium sulfate in 734g. Then, divide the moles by the volume of solution in liters to get the molarity. Remember to convert grams to moles using the molar mass of lithium sulfate (Li2SO4).
