It depends on hour
example: for 4 hour back up
35AH means 35 amps/1 hr
for 4 hrs : 35x4 = 140 amps
Solar watt required - 140 x 12 (Vx I) = 1680 watts
Please let me know this calculation is correct or not
rshashiku@gmail.com
You can't charge the battery with those 245 watts unless they are being 'pumped into' the battery at a higher voltage than the battery puts out. If you can exceed the voltage of the battery, that 245 watts will definitely charge a battery.
To charge any battery the voltage of the input must be more than the battery's output.
1 watt will do the job.
about 500watts/meters of irradiance
You sure can! I charge a marine battery with a 75 watt panel and it goes from a fairly good discharged state to fully charged in about four days.
There is too much information there. Charging a 100 amp-hour battery fully would take 18 hours at 5.5 amps, or 6 hours at 16.67 amps. At 5.5 amps the power would be 12x5.5 or 66 watts, and this is the rating of the solar panel required. That would be about 0.4 of a square metre.
For calculation purposes 1 HP is equal to 746 watts. So you have a total of 746 x 7 = 5222 watts. The amperage will be A = W/V = 7222/12 = 435 amps. You can not start the motor directly off of the solar panel. You would need a large 12 VDC parallel connected battery bank to obtain the amperage capacity to start the motor. The solar panels would be connected to the battery bank and used to charge the batteries after the start.
123mb
36 No's of 300w solar modules required
Solar panels can make enough watts to power your whole house if you have enough of them. Some solar panels will generate 50 watts, 80 watts or 120 watts.
The power required is(6) times (the amperes of current the radio draws when it operates) watts.
Yes, you can. The alternator on your boat is voltage regulated, so it will automatically taper off the charge current to maintain about 14.6 volts regardless of what the solar panel is doing. The panel is not regulated if you do not have a charge regulator installed between it and the battery, but at 5.5 watts, the most it will put out is about one half an amp. As a rule, you can take the current rating on a panel and divide it by 50, and as long as the amp hour capacity of the battery is not less than the resultant number, you do not need a charge controller, the panel will never put out enough current to overcharge the battery. If the sun is shining while the motor is running, the alternator will simply reduce its output enough to accomodate the panel, no other action is required. If you want to read more about this, look in the library for a book called, "The Complete Battery Book," by Richard Perez. Take care, Rudy