Prime factor the 2.45 = 9x5 = 3x3x581 = 9x9 = 3x3x3x3Your LCM will contain all the multiples of both numbers. 45 has 2 threes and 1 five. 81 has 3 threes. Together you need 4 threes and 1 five to cover both numbers. Therefore your LCM = 3x3x3x3x5 = 405.
There are four threes in a standard deck of cards.
tn = 3n or 3*3* ... *3 (where there are n threes.)
i
210
Prime factor the 2.45 = 9x5 = 3x3x581 = 9x9 = 3x3x3x3Your LCM will contain all the multiples of both numbers. 45 has 2 threes and 1 five. 81 has 3 threes. Together you need 4 threes and 1 five to cover both numbers. Therefore your LCM = 3x3x3x3x5 = 405.
there are a ton of threes and it's 11 3s
There are four threes in a standard deck of cards.
tn = 3n or 3*3* ... *3 (where there are n threes.)
99 / 3 = 33 threes 100/3 = 33.33 threes which rounded would be equal to 33 threes
i
How many 3s are in 15
ii
15
12
210
35