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Aa=2

Bb=2

CC=1

dd=1

EE=1

2 x 2 x 1 x 1 x 1 = 4

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13y ago
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13y ago

there is no variation for the alleles C and D. alleles A and B are heterozygous there is variation for these two (Aa and Bb)

2^2=4

therefore, 4 different gametes are possible

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11y ago

8

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Q: How many unique gametes could be produced through independent assortment be an individual with the genotype AaBbCCddEE?
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