Seven
An iodine atom has seven valence electrons.
Iodine atom has 7 valence electrons, whereas Iodide ion has 8 valence electrons.
CI4, or carbon tetraiodide, contains one carbon atom and four iodine atoms. Carbon has 4 valence electrons, while each iodine atom has 7 valence electrons. Therefore, the total number of valence electrons in CI4 is 4 (from carbon) + 4 × 7 (from iodine) = 4 + 28 = 32 valence electrons.
There would not be any. The electrons and protons would be equal so there would not be any that are leftover to use.
7 valence electrons in iodine
Iodine is in group 17 of the periodic table, which means it has seven valence electrons. When iodine is the central atom in a molecule, it typically retains all seven of its valence electrons unless it forms bonds with other atoms. In such cases, some of these electrons are shared with surrounding atoms, but the total number of valence electrons associated with the iodine remains seven.
There is no Iodone atom, there is however an Iodine atom that has seven valence electrons or seven electrons in outermost shell.
There are 14 valence electrons in I2. Each iodine atom contributes 7 valence electrons, resulting in a total of 14 valence electrons in the diatomic molecule.
Iodine pentafluoride has 7 valence electrons.
An iodine atom has 46 core electrons. Core electrons are the inner electrons that are not involved in chemical bonding. In the case of iodine, the core electrons would include the 36 electrons found in the first four electron shells.
In IF3, iodine (I) has 7 valence electrons and each fluorine (F) has 7 valence electrons. Thus, the central iodine atom in IF3 is surrounded by 21 electrons from the three fluorine atoms (7 electrons each).
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