For a three-phase, three-wire, system there are three conductors called 'line conductors', and there is a voltage between any pair of line conductors, so there are three voltages.
For a three-phase, four-wire, system there are four conductors: three 'line conductors' and a 'neutral' conductor. So there are three line voltages (voltages between lines) and three phase voltages (voltages between any line conductor and a neutral conductor).
There is no 'total voltage' in a three-phase system. There are three line voltages and three phase voltages.
Generator coils generate the voltage, motor coils use the generated voltage.
The term, 'unbalanced system' refers to an unbalanced load. Under normal circumstances, an unbalanced load leads to unbalanced line currents. The line voltages are determined by the supply and remain symmetrical, even when the load is unbalanced. As your question refers to a 'line to neutral' voltage (i.e. a phase voltage), you must be referring to a star (wye) connected load, in which case the phase voltage (line to neutral voltage) is 0.577 (the reciprocal of the square-root of 3) times the line voltage (line to line voltage).
depending on 1phase or 3phase voltage motor , the amphere requirement is found outfor 3phase AC motor use this formula: (HP x 746)/(1.73 x E x Eff x PF)for 1phase AC motor : (HP x 746) / (E x Eff x PF)
In a 3 phase system, the voltage measured between any two phase is called line to line voltage.And the voltage measured between line to neutral is called phase to neutral (line to neutral) voltage.AnswerThere is no such thing as a 'phase-to-phase' or a 'phase-to-neutral' voltage. The correct terms are 'line-to-line' and 'line-to-neutral'.The voltage between any two line conductors is called a line voltage.In a three-phase, three-wire, system, the line voltage is numerically equal to the phase voltage.In a three-phase, four-wire, system, the voltage between any line conductor and the neutral conductor is called a phase voltage. The line voltage is 1.732 times larger than the phase voltage.
There is no 'total voltage' in a three-phase system. There are three line voltages and three phase voltages.
Ohm's Law - V = IR.
A-for star connectionE(line)=1.73E(Phase)I(line)=I(Phase)&B-for delta connectionE(line)=E(Phase)I(line)=1.73I(Phase)
It is not advisable to run lower voltage motor on a higher voltage.
This is a voltage drop question. A voltage must be stated to answer this question.
Generator coils generate the voltage, motor coils use the generated voltage.
Your question is not clear. Are you asking how you can obtain a single-phase supply from a three-phase system? If so, then it depends on the type of three-phase supply and the voltage you require. For example, a three-phase, three-wire, system, single phase is obtained between any two line conductors. For a three-phase, four-wire, system, single phase is obtained either between any two line conductors, or between any line conductor and the neutral conductor. In the case of the latter, two voltages are available, a line voltage and a phase voltage, with the line voltage being 1.732 x larger than the phase voltage.
Phase to Phase voltageCorrection to the above answer:There is no such thing as a 'phase-to-phase' or 'phase-to-ground' voltage. The correct terms are 'line-to-line' (or 'line voltage') and 'line-to-ground' (or 'phase voltage'). Transmission-line voltages are line-to-line (or 'line') voltages.
50 kVA is 16.667 kVA per phase and you divide that by the phase voltage. Current = 16667 / 277 = 60 Amps
A voltage is applied to a signal line. The voltage of the line changes gradually from 0 to +V. The "edge speed" is the rate of change of voltage of the line. A voltage is applied to a signal line. The voltage of the line changes gradually from 0 to +V. The "edge speed" is the rate of change of voltage of the line.
The term, 'unbalanced system' refers to an unbalanced load. Under normal circumstances, an unbalanced load leads to unbalanced line currents. The line voltages are determined by the supply and remain symmetrical, even when the load is unbalanced. As your question refers to a 'line to neutral' voltage (i.e. a phase voltage), you must be referring to a star (wye) connected load, in which case the phase voltage (line to neutral voltage) is 0.577 (the reciprocal of the square-root of 3) times the line voltage (line to line voltage).
Phase, if you are referring to line, as power line from pole.