...90 volts...
Using Ohms Law, the answer is 120/0.5 = 240 Ohms.
you divide the volts by the ohms
The resister always being used to save components to damage by absorbing extra voltages, diode works on 0.7 volts n usually having 15 volts from the source so extra voltages drops across the resister and it works safely.
Total resistance (thevinen resistance) = 4 + 8 Total voltage = 12 volts. Ohms law: I = V / R Therefore I = 12/12 = 1 amp.
Ohm's law: Voltage equals current times resistance. 8 amperes times 24 ohms equals 192 volts.
5 amps. Use Ohm's Law: I = V/R = 90/18 = 5
Using Ohms Law, the answer is 120/0.5 = 240 Ohms.
== == It is a 12 volt system. The alternator should put out 13.5 to 14.5 volts with the engine running.== == It is a 12 volt system. The alternator should put out 13.5 to 14.5 volts with the engine running.
What is the voltage drop running through resistor one
The capital Greek letter Ω (omega) is the symbol for Ohms - the unit of resistance. A 1.5Ω resister is a resistor with quite a low resistance. If a voltage of 1.5 Volts is applied across it, a current of 1 Amp[ere]s will flow through it.
you divide the volts by the ohms
The resister always being used to save components to damage by absorbing extra voltages, diode works on 0.7 volts n usually having 15 volts from the source so extra voltages drops across the resister and it works safely.
Total resistance (thevinen resistance) = 4 + 8 Total voltage = 12 volts. Ohms law: I = V / R Therefore I = 12/12 = 1 amp.
If running at 120 volts that is 8.33 ampsIf running at 120 volts that is 8.33 amps
The electrical system is 12 volt negative ground. Really about 13.6 volts while the engine is running, though.
Ohm's law: Voltage equals current times resistance. 8 amperes times 24 ohms equals 192 volts.
12 volt system A fully charged 12 volt battery will have 12 to 12.7 volts. With you engine running you should have 13 to 13.5 volts