The number of watts produced by a current of 1.25 amperes can only be known if you also know either the applied voltage which caused that current to flow (W=I x E); or if you know the resistance through which the current flows. (W= I2 R).
1000 milliamperes = 1 amp. Assuming a resistive load, amps = watts / volts = .125 amps or 125 milliamperes
watts = amps (times) voltage watts (divided by) voltage = amps 140 (div by) 120 = 1.66 140 (div by) 125 = 1.12
These are not convertible quantities. The same way that you cannot convert seconds into pounds. Or pounds into miles per hour. If you reconstituted your question into the form of "I have a device that draws 2 amps at 125 volts, how many Watts is it consuming?" we'd be off to the races. Hope that helps.
Depends on the voltage output, in a 12 Volt system 12.5 Amps equals 150 Watts, the equation is, (Amps x Volts)= Watts <<>> 12.5 amps is zero watts. Watts is the product of amps x volts. Without the voltage value an answer can not be given.
12.5 centimetres are in 125 millimetres.
Depends on the voltage. If you multiply the voltage with the amperes you get watts. If it's a 400V group you have 3 times 230V 125A
1 horsepower is equal to 747.5 watts. 125 hp therefore = 93.2kW
1000 milliamperes = 1 amp. Assuming a resistive load, amps = watts / volts = .125 amps or 125 milliamperes
3 watts to 125 watts.
100
watts = amps (times) voltage watts (divided by) voltage = amps 140 (div by) 120 = 1.66 140 (div by) 125 = 1.12
These are not convertible quantities. The same way that you cannot convert seconds into pounds. Or pounds into miles per hour. If you reconstituted your question into the form of "I have a device that draws 2 amps at 125 volts, how many Watts is it consuming?" we'd be off to the races. Hope that helps.
Two resistors in series, one 5 ohms and one 2 ohms, with a current of 5 amperes, will have a power dissipation of 175 watts. Ohm's law: Voltage = current times resistance E1 = I R1 = (5) (5) = 25 volts E2 = I R2 = (5) (2) = 10 volts Power law: Power = current times voltage P1 = I E1 = (5) (25) = 125 watts P2 = I E2 = (5) (10) = 50 watts PT = P1 + P2 = 125 + 50 = 175 watts
Yes, you can substitute a 250 volt fuse in place of a 125 volt fuse. You just can't go the other way around. As far as 1.5 amperes in place of 3 amperes, well, you've got a problem there because the fuse will blow at about 1.5 amperes instead of 3 amperes, so the intended load will not be met. All of this, of course, assumes that the physical size of the fuse is the same. Bottom line is never substitute fuses.
Depends on the voltage output, in a 12 Volt system 12.5 Amps equals 150 Watts, the equation is, (Amps x Volts)= Watts <<>> 12.5 amps is zero watts. Watts is the product of amps x volts. Without the voltage value an answer can not be given.
It generates 12V unless its an older 6V model the correct question is probably how many Watts does it produce
Ohm's Law: Voltage is current times resistance.4 amperes times 125 ohms equals 500 volts.Power Law: Watts is voltage times current4 amperes times 500 volts equals 2000 watts.WARNING: This is a lot of power. Do not attempt to duplicate this in the labwithout the proper equipment as there is great risk of fire.=============================Power dissipated by a resistance = (current)2 x (resistance) = (4)2 x (125) = 2000 W.As the first contributor noted, this is a healthy amount of power dissipation. It's notnecessarily dangerous if you're prepared for it . . . hair dryers, toasters, baseboardheaters, electric stoves and furnaces do it every day. But if you're in the engineeringlab playing with a power supply and a bagful of 1/2-watt resistors, then things will notwork out as the math predicts, since the resistors are likely to explode catastrophicallybefore you have a chance to read the ammeter.