Volts x Amps = Watts, divide with 1000 and you get kilowatts.
100 KW divided by 415 volts is 241 amperes. Power = voltage times current, so current = power divided by voltage.
415*800*pf
Wire sizing is determined by the amount of amperage that the connected device draws. Look on the nameplate of the motor and state the amperage. Then the question can be answered.
10000 = 415 * i i = 10000/415 = 24 a <<>> The formula you are looking for when KVA is known is I = KVA x 1000/1.73 x E = 10000/1.73 x 415 = 10000/240 = 41.6 amps.
The answer is 40,000 divided by 415 or 96.38 Amps. Watts is volts times amps.
Volts x Amps = Watts, divide with 1000 and you get kilowatts.
That would depend on the power output (watts) of the circuit. Volts times the Amperage equals the Wattage of the circuit. You do not have enough information in your question. Volts is the force applied to move the electrons in the circuit, and amps are a measure of the quantity of electrons moved through the circuit over time. Thus a circuit of 415 volts and 1 ampere will deliver 415 watt-hours of power. Yet a circuit of 1 volt at 415 amps will deliver the same 415 watt-hours of power, but with less force.
There are zero amps in a 6kW 3 phase heater. Amperage is the result of dividing the Watts by the Voltage. A = W/E. Without stating the voltage the heater operates on the amperage can not be calculated.
100 KW divided by 415 volts is 241 amperes. Power = voltage times current, so current = power divided by voltage.
X / 415 = 80 / 220 = 151 amps
Power = voltage times current, and the power loss is the loss in the line, I^2 * R. At 11,000 volts, the current will be (11,000 / 415 = ) 3.77% of what it is at 415 volts. So the power loss in the line at 11,000 volts will be (3.77% ^2 = ) .14% of what it is at 415 volts.
Since watts = volts times amps times 1.73 times power factor (for a three phase motor): W = E * I * 1.73 * PF Solving for I: I = W / (E * 1.73 * PF) Lets say your motor has a PF of 0.85: I = 10000 / (415 * 1.73 * 0.85) I = 16.39A If this is for your homework (I hope not) and PF is not given, then you will substitute 1.0 for the PF and, of course, arrive at a different answer!
1 HP=746 watts 15 HP=11,190 watts Ohm's Law says Current (in Amps) = Power (in Watts) divided by Voltage (in Volts) 11,190 watts divided by 415 volts = 26.96 amps. <<>> For a three-phase motor each phase supplies one third of the power, so that is 5 HP on each phase. A 415 v supply has a line-to-neutral voltage of 240 v, and 3730 watts would therefore required 3730/240 amps, or 15.54 amps. However due allowance must be made for (i) the power factor and (ii) the conversion efficiency. This would increase the current by an estimated 20% so the current is therefore estimated to be 19 amps.
415 volts
1 ton of air-con is defined as 3577 watts Therefore 20 tons is 71.5 kW. On a 240 v 3-ph system the current for that is 100 amps, assuming a 240 v line-to-neutral voltage, equivalent to a phase-to-phase voltage of 415 v.
It depends on the voltage: 208 v 14 amps, 415 v 7 amps, 480 v 6 amps.