it is a combination: 9!/4!=9 x 8 x 7 x 6
If there is a group of 3 coloured balls, then any groups of 2 balls selected from it will be considered as a combination, whereas the different arrangements of every combination will be considered as a permutation
yes form cayleys theorem . every group is isomorphic to groups of permutation and finite groups are not an exception.
{123, 132, 213, 231, 312, 321}
The answer depends on whether xy are commutative numbers or operators in a permutation group.
Cayley's theorem:Let (G,$) be a group. For each g Є G, let Jg be a permutation of G such thatJg(x) = g$xJ, then, is a function from g to Jg, J: g --> Jg and is an isomorphism from (G,$) onto a permutation group on G.Proof:We already know, from another established theorem that I'm not going to prove here, that an element invertible for an associative composition is cancellable for that composition, therefore Jg is a permutation of G. Given another permutation, Jh = Jg, then h = h$x = Jh(x) = Jg(x) = g$x = g, meaning J is injective. Now for the fun part!For every x Є G, a composition of two permutations is as follows:(Jg ○ Jh)(x) = Jg(Jh(x)) = Jg(h$x) = g$(h$x) = (g$h)$x = Jg$h(x)Therefore Jg ○ Jh = Jg$h(x) for all g, h Є GThat means that the set Ђ = {Jg: g Є G} is a stable subset of the permutation subset of G, written as ЖG, and J is an isomorphism from G onto Ђ. Consequently, Ђ is a group and therefore is a permutation group on G.Q.E.D.
A permutation is an arrangement of objects in some specific order. Permutations are regarded as ordered elements. A selection in which order is not important is called a combination. Combinations are regarded as sets. For example, if there is a group of 3 different colored balls, then any group of 2 balls selected from it will be considered as a combination, whereas the different arrangements of every combination will be considered as a permutation.
If there is a group of 3 coloured balls, then any groups of 2 balls selected from it will be considered as a combination, whereas the different arrangements of every combination will be considered as a permutation
A permutation group is a group of permutations, or bijections (one-to-one, onto functions) between a finite set and itself.
yes form cayleys theorem . every group is isomorphic to groups of permutation and finite groups are not an exception.
group of people chosen to make decisions in court
This situation is a combination, since from a group of 9 people, 4 are chosen and the order in which they are chosen is not important. So we have9C4 = (9 x 8 x 7 x 6 )/(4 x 3 x 2 x 1) = 126.The following explanation will tell you why we got this result.The first person can be any one of 9.The second person can be any one of the remaining 8.The third person can be any one of the remaining 7.The fourth person can be any one of the remaining 6.The number of ways to make this choice of 4 people is (9 x 8 x 7 x 6) = 3,024.This is a permutation, and that's what the question asked for when it asked ... "How many ways ... ".But not all of the groups chosen in these 3,024 ways are different groups. In fact, each differentgroup will show up 24 times, because 4 people can be arranged (4 x 3 x 2 x 1) = 24 ways.So the number of combinations, i.e. different groups of 4 people, is (3,024 / 24) = 126.
{123, 132, 213, 231, 312, 321}
Representatives.
A large group of people that thought they were chosen by God.
He was selected by a group of wise people who are chosen by people in elections.
If order matters, it is a permutation. If the order doesn't matter, then it is a combination. like the person says if the word problem says anything about a GROUP its combination but if it says anything about order, lines, places, 1st, 2nd or ,3rd then it is permutations
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