First, count how many letters you have--A, B, C, D, E, and F--6.
Then, the problem is the number multiplied by the ones below it. 6x5x4x3x2x1.
You can get rid of the one, because anything multiplied by 1 is itself.
6x5x4x3x2=720.
You can arrange these six letters in 720 possible ways.
If the row could be vertical or horizontal, the number doubles to 1440.
se foramula is
(length of string)!/(product of factorial of length of all repeated string)
e.g
abcdef = 6!/0!
abbcdef = 7!/2!
24 ways
There are 24 ways to arrange 4 people in a row.
There are 4 characters.They can be arranged within themselves so they can be arranged in 24 ways.[Note : The formula for this is n! if there are n characters.]
7! = 5040 ways.
24
40320
You are arranging 70 plants in a rectangular garden with the same number of plants in each row. How many ways can you arrange the garden
They can be arranged 5! or 120 ways.
how many ways can 8 letters be arranged
8 ways
i think a total of 6 but i am not sure
Four ways:1 row with 6 in each row.2 rows with 3 in each row.3 rows with 2 in each row.6 rows with 1 in each row.
6! = 6 factorial = 1x2x3x4x5x6 = 720