Get moles by;
Molarity = moles of solute/Liters of solution
0.50 M KNO3 = moles KNO3/2.0 L
= 1.0 mole KNO3
Now find grams of 1.0 mole KNO3
1.0 mole KNO3 (101.11 grams/1 mole KNO3)
= 101.11 grams KNO3 needed
call it 100 grams
dont ask the internet to do your homework it wont go well
Instead of waiting for the answer, I ended up solving it. lol 300grams of H20 X 110grams of KNO3/100 grams of H20 = 330 grams of KNO3 The grams of H20 both cancel out and leave you with 330 grams of KNO3 Containing the solubility of KNO3. At 60 degrees celsius the KNO3 grams were 110, which is (over) / 100grams of H20. Hope this helps with this workbook problem :)
Quite a few! 427.4 grams KNO3 (1 mole KNO3/101.11 grams)(6.022 X 1023/1 mole KNO3) = 2.546 X 1024 molecules of potassium nitrate -----------------------------------------------------------
Why 100 ml solution of KOH3 can not hold more than 37gm of KNO3 in dissolved state
KNO3 140 g/100 g of water is a saturated solution at about 70 to 75 oC. The solubility change with temperature and it need to be stated for reference temperature. For standard room temperature, KNO3 is saturated at 38.3 g/ 100 g water.
It can be separated by boiling off the water or crystallizing the KNO3 from solution
dont ask the internet to do your homework it wont go well
1.0 molal
Instead of waiting for the answer, I ended up solving it. lol 300grams of H20 X 110grams of KNO3/100 grams of H20 = 330 grams of KNO3 The grams of H20 both cancel out and leave you with 330 grams of KNO3 Containing the solubility of KNO3. At 60 degrees celsius the KNO3 grams were 110, which is (over) / 100grams of H20. Hope this helps with this workbook problem :)
kno3
Quite a few! 427.4 grams KNO3 (1 mole KNO3/101.11 grams)(6.022 X 1023/1 mole KNO3) = 2.546 X 1024 molecules of potassium nitrate -----------------------------------------------------------
Why 100 ml solution of KOH3 can not hold more than 37gm of KNO3 in dissolved state
It doesn't
More than 45,5 g KNO3.
The molecular weight of potassium nitrate (KNO3) is 101.1 grams/mole.K = 39.1 + N = 14.0 + O = 3*16.0 = 101.1Now divide 6.5 by 101.1 to calculate # of moles => 0.064 moles KNO3
As the solution is cooled, the solubility of the solution decreases and a precipitate will form.
The solution will be neutral to nature.