By the definition of molarity, which is mass of solute in moles divided by solution volume in liters, 250 ml of 0.15 M NaCl*
solution requires (250/1000)(0.15) or 0.0375 moles of NaCl.
Each liter of 2M NaCl
solution contains 2 moles of NaCl.
Therefore, an amount of 0.0375 moles of NaCl
is contained in (0.0375/2) liters, or about 18.75 ml of the 2M NaCl,
and if this volume of the more concentrated solution is diluted to a total volume of 250 ml, a 0.15 M solution will be obtained.
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*Note correct capitalization of the formula.
Dilute it.
117 grams of NaCl
You need to know the amount of NaCl.
The volume is 342 mL.
[117(g NaCl) / 58.5(g NaCl/mol NaCl)] / 40.0(L solution) = [117/58.5]/40.0 = 2.00(mol NaCl) / 40.0(L) = 0.0500 mol NaCl / L solution = 0.0500 M
molarity of 5% NaCl solution would be 1.25M.
Dissolve some NaCl in water and add it up to 250 mL.
Sodium chloride is a solute when is dissolved in water (the solvent).
A 0.0% NaCl solution is a solution with absolutely no NaCl.
You have to evaporate (by open boiling) 45 mL of the 75 mL 2M NaCl solution thus reducing the volume to 30 mL 5M NaCl.
The Molecular Weight of NaCl = 58.5 So to make 1L of 4M NaCl solution you need 4*58.5=234g of NaCl So to make 100mL of the above solution you need 23.4 grams of NaCl
Gram percent is the number of grams of a solute per 100 grams of a solution. For example, if a solution of NaCl and water was said to have a 0.02g% of NaCl, this would mean that for 100g of saline solution, 0.02 of those grams are salt. Since 1L of water weighs 1kg (at normal conditions), there would be .2g of NaCl in 1L of a 0.02g% NaCl solution.
If 10 is 10 molar for you, this is a saturated solution of NaCl.
NaCl is neutral so it will produce a solution with a pH of 7 in any concentration.
It depends on the final solution Volume you want to prepare. For 100ml of a 6M NaCL solution, you add 35.1g of NaCl to water until you reach 100ml. Dissolve and autoclave for 15 mins.
Sodium chloride is a salt; the water solution is neutral.
Dilute it.