RMM of CuSo4 . 5H2O = 160 + 5x18 = 250 g
How much contain gram in 100 mL of 0.050 M CuSO4 solution is -
Solution:
= 0.050 x 100/1000 x 250
= 0.050x4 (100)/ 16
= 1.25 g
heat a solution to evaporate the water off
Cr(NO3)3-238g/mol Moles in 500ml, 2.08x500/1000=1.04mol. Mass of Cr(NO3)3=1.04x238=247.52g
it has to be prepared using methanol or ethanol at the concentration we required.
h
The answer is 20,15 mL.
heat a solution to evaporate the water off
To prepare 1 M CaI aqueous solution, dissolve 29.4 g in a total volume of 100 mls, or 294 g in a total volume of 1 liter.
Denpending of the concentrations, you can use only mechanical agitation and elevate temperature for 5 to 15 minutes.
Cr(NO3)3-238g/mol Moles in 500ml, 2.08x500/1000=1.04mol. Mass of Cr(NO3)3=1.04x238=247.52g
it has to be prepared using methanol or ethanol at the concentration we required.
it is very easy to prepare working solution from a stock solution we use the formula for this purpose which is: C1V1 = C2V2 C1 is the concentration of the stock solution V1 required volume from the stock solution C2 concentration of the working solution V2 volume of the working solution
h
The answer is 20,15 mL.
30 grams
24 g
This depends on your experiment.
40 grams, this is the 1M NaOH standard laboratory solution.