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Cr(NO3)3-238g/mol Moles in 500ml, 2.08x500/1000=1.04mol. Mass of Cr(NO3)3=1.04x238=247.52g

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Q: How many grams of CrNO33 are required to prepare 500.0 mL of an aqueous solution which has a Cr3 concentration of 2.08 M?
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