The density of oxygen is 1,429 g/L. The density of air is 1,290 g/L.
P1*V1 = P2*V13.0 ATM * 5.0 L = 1.0 ATM *V2 V2 = (3.0 ATM / 1.0 ATM) * 5.0 L V2 = 15L
Because of different structure and bonds between oxygen atoms
There are two oxygen atoms in each molecule (hence the prefix di). Ten CO2 molecules would require twenty oxygen atoms
Ideal gas law.PV = nRT(1.00 atmosphere)(30 L) = n(0.08206 L*atm/mol*K)(298.15 K)n(moles O2) = 30/24.466= 1.2 moles oxygen gas================
It depends on how much FiO2 you want to deliver and what the patient will tolerate. For most patients a nasal cannula will be sufficient at 1-6 L/M. The FiO2 will go up 4% with each liter of flow, so 1 L/M = 24%, 2 L/M = 28% up to 6 L/M = 44%. If you need more than that then you can try a venturi mask, which will give a precise FiO2 of 28-55%, or a non-rebreather which gives up to 95%. If you do use a simple mask, which I don't recommend because people don't seem to understand them, make sure the flow is at least 5-10 L/M. A simple mask will deliver about 35-50% FiO2. However, running a simple mask at less than 5 L/M will not provide enough flow of oxygen to clear the mask of CO2 so your patient will be rebreathing their CO2.
10 Liters is most manufacturer's recommended maximum
The density of oxygen is 1,429 g/L. The density of air is 1,290 g/L.
9
14.2 l of H2S and 21.3 l of oxygen
If the density of oxygen atSTP is 1,429 g/L the mass of 180 L is 257,22 g.If the mole of oxygen (O2) is 15,999 g the number of moles is 16,077.
3 L = 3000 mLTo convert from L to mL, multiply by 1000.
P1*V1 = P2*V13.0 ATM * 5.0 L = 1.0 ATM *V2 V2 = (3.0 ATM / 1.0 ATM) * 5.0 L V2 = 15L
lithium is with l & oxygen is with o
0.667
3 L = 3000 mL 1893 mL = 1.893 L 3 L + 1.893 L = 4.893 L 3000 mL + 1893 mL = 4893 mL
The solubility of oxygen is higher in cold water. For example, at 0 degrees C saturation is 14.7 mg/L; and at 30 degrees C it is only 7.4 mg/L. That's why some fish struggle in very warm water; not as much oxygen available.