I= Ah/h = 80Ah/10h = 8A
The current output is governed by the load resistance of the circuit. The battery will try and supply as much current as needed up until the battery goes dead.
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How much you got paid for a year
That does not depend directly on the brightness of the bulb, it depends on the current drawn by the bulb (which depends on the efficiency of the bulb). For example an incandescent bulb will draw much more current than a much brighter CFL bulb or LED bulb. Therefor switching to an brighter LED bulb can make the battery last much longer while switching to a brighter incandescent bulb will make the battery run down quicker.
The current depends on what is connected to the battery's terminals. If nothing is connected to it, then there is no current, and the battery lasts quite a while. In general, the current is 1.5/resistance of the external circuit connected to the battery until that number gets too big, and then the voltage of the battery sags, because it can't deliver that much current.
Watts are the product of amps times volts. The amperage in a circuit is governed by the resistance of the load. A battery just supplies the potential as voltage, the load determines how much current is going to be drawn out of the battery. Batteries are rated in amp/hours. This means how long can a battery maintain a specific amperage over a period of time.
The load indicator is a measure of how much current is drawn from the battery. Nore load is more current which means the battery won't last as long, and the driver may run out of power before getting to the destination. The same thing is true of petrol cars, and heavy footed drivers get the same result.
Doesn't work like that. Current drain is dependent on the (internal resistance of the battery and the) resistance/power requirements of what's connected to the battery. If shorted out, the current - unless the battery is fused or otherwise protected - can go into tens of amps.
That can vary a lot, depending on the size of the battery. The "volt" is not an indication of energy stored. It simply means that (on average), each electron is pushed at a certain energy. To get the total energy, you would also need to know how much current it can provide, and for how long. The total energy can be calculated as the product of the voltage, the current, and how long this current flows (assuming a constant current; otherwise you would have to integrate).
It depends on how its connected and how much current the camera needs to run on. The "1050ma" figure is the capacity of the battery not how much current the camera uses and it should read 1050mah which is a capacity measurement not a current measurement.
None. The amps (current) comes from the battery and/or the alternator. The fuse box merely distributes this current to various loads such as lights, ignition, electronics, etc. The total current available is governed by the size of battery and charging system. The amount of current available on a single circuit is governed by the size of the wire and the rating of the fuse you plug in. One or the other will eventually melt if too much current is drawn. If you have the proper fuse in place, it will always melt first, protecting the wire.