Assuming the density of Aluminum is 2.7 g/cubic cm
Then 1.259 kg occupies (1.259 x 1000 /2.7) cm3 = 466.3 cm3
1 kg 250g is equal to 1250 grams.
just 1250 kg :))
800 kj
There are 1000 grams in a kilogram. To convert 1250 grams to kilograms, you divide by 1000. Therefore, 1250 grams is equal to 1.25 kilograms.
To vaporize aluminum, you need to consider its heat of vaporization, which is approximately 10,700 kJ/kg. For 2 kg of aluminum, the total energy required would be 2 kg × 10,700 kJ/kg, equating to about 21,400 kJ. Therefore, around 21.4 million joules of energy is needed to vaporize 2 kg of aluminum.
526
To calculate the energy required to vaporize 2 kg of aluminum, we use the heat of vaporization of aluminum, which is approximately 10,900 J/kg. Therefore, the energy required is 2 kg × 10,900 J/kg = 21,800 J, or 21.8 kJ. This is the amount of energy needed to convert 2 kg of aluminum from a liquid to a vapor at its boiling point.
1250 kg
1.25 kg
1.25 kg = 1250 g
To vaporize aluminum, you need to know its heat of vaporization, which is approximately 10,700 kJ/kg. Therefore, to vaporize 2 kg of aluminum, you would require about 21,400 kJ (2 kg × 10,700 kJ/kg). This calculation assumes that the aluminum is already at its melting point and that the vaporization occurs under standard atmospheric conditions.
1.25 tonnes.