Depending on some textbooks it can differ somewhat, but 1 mole of Na weighs 22.99 grams, and 1 mole of Cl weighs 35.45 grams. So if you combine the two.
Na + Cl --> NaCl
Then you would just add the two up to give you 58.44 g/mol.
Hope that helps.
--Zdrum
1.409 moles chlorine (35.45 grams/1 mole Cl) = 49.95 grams of chlorine ==================
The chemical formula for sodium hypochlorite is NaClO, and so each mole contains 1 mole of Na and 1 mole of Cl and one mole of O. Now, what is the 5.25 in your question? Is that 5.25 moles, or 5.25 grams, or 5.25 mg? If it's grams, then you divide the 5.25 g by the molar mass of NaClO to get moles NaClO. After that, you multiply that number by 35.5 g/mole Cl to get grams of Cl. Divide that by 1000 to get mg of Cl and then since it is in 500 ml (0.5 L) multiply that by 2 to get mg/liter which is the same as ppm.
1) Get the chemical formula to determine the number of each type of atom present in the compound. 2) Multiply the atomic weight (get it from the periodic table) of each element by the number of atoms of that element present your specific compound 3) Do the Sum in unit grams/mole NaCl (1x23 grams/mole Na) + (1x 35.5 grams/mole Cl) = 58.5 grams/mole NaCl
Find the atomic or molecular weight of each and multiply it by the number of moles. atomic weight of carbon is 12 g/mole. atomic weight of chlorine is 35.45 g/mole molecular weight of fructose is 180.16 g/mole So just find the total grams. 10 moles Carbon * 12g/mole Carbon = 120 grams carbon 3 moles Chlorine * 35.45g/mole Chlorine = 106.35 grams Chlorine 1 mole Fructose * 180.16 g/mole Fructose = 180.16 grams Fructose So the answer is 1 mole of fructose.
This question doesn't make sense. You may mean what is the molecular weight of the chloride ion. In that case it's about 35.5 grams per mole. A mole is a number (called Avagadro's number) that is representative of the amount of Carbon atoms in 12 grams of carbon12. Since different elements weigh different amounts, it's a way to compare the number of molecules or atoms present in a mixture or compound. But for simplicity's sake, just think of it as a number you express with a word--like a dozen means twelve. However, a mole is a very large number. It's 6.022 × 1023 or 602,200,000,000,000,000,000,000. So to have one mole of hot dogs, you would have 6.022 × 1023 hot dogs. The molecular weight is expressed in grams per mole. So the chloride ion (Cl-) has a molecular weight of 35.5 which means that one mole of chloride ions weighs 35.5 grams. You can then use this molecular weight to figure out how many moles of an element are in a certain number of grams. If you have 71 grams of chloride, you know that you have 2 moles by multiplying the amount of grams (71g) × 1 mol/35.5g = 2 mols
1.409 moles chlorine (35.45 grams/1 mole Cl) = 49.95 grams of chlorine ==================
10.0gCl*1 mole Cl*22.4Cl L/ 35.45g Cl* 1mole Cl=6.32L Cl
One mole of chloride (Cl-) to one mole of Ag+ ions: Cl- + Ag+ --> AgCl(s)
The chemical formula for sodium hypochlorite is NaClO, and so each mole contains 1 mole of Na and 1 mole of Cl and one mole of O. Now, what is the 5.25 in your question? Is that 5.25 moles, or 5.25 grams, or 5.25 mg? If it's grams, then you divide the 5.25 g by the molar mass of NaClO to get moles NaClO. After that, you multiply that number by 35.5 g/mole Cl to get grams of Cl. Divide that by 1000 to get mg of Cl and then since it is in 500 ml (0.5 L) multiply that by 2 to get mg/liter which is the same as ppm.
1 mole Cl = 35.453g Cl 28.4g Cl x 1mol Cl/35.453g Cl = 0.801 mole Cl
They use a number called a mole. This many atoms of an element equals its atomic weight in the periodic table. Molecular weight is the sum of atomic weight. Silver has an atomic weight of 108 grams/mole and Chlorine is 35.4 grams/mole. This makes AgCl 108 + 35.4 = 143.4 grams/mole. The % Chlorine is the atomic weight of Chlorine divided by the molecular weight of AgCl. 1 mole of AgCl would contain 35.4 grams / 143.4 grams = 25% Chlorine by weight. 1.22 grams AgCl would contain (0.25)*(1.22) = 0.30 grams of Cl. To find the Chlorine in the unknown, divide the weight of Chlorine from the experiment by the initial weight of the unknown. 0.30 grams / 0.63 grams = 0.48 = 48% Cl by weight.
Mole = Mass/RMM Ar for Na=23 & Ar for Cl = 35.5 Therefore 1mole = Mass / (35.5+23) 1 mole of NaCl is 58.5g Mole = Mass/RMM Ar for Na=23 & Ar for Cl = 35.5 Therefore 1mole = Mass / (35.5+23) 1 mole of NaCl is 58.5g But that can be misleading. NaCl does not form into molecules (and salts in general do not). If you dissolve 58.5g of NaCl into water, it will dissociate into ions, and there will be 2 moles of particles in solution: 1 mole of Na+ ions, and 1 mole of Cl- ions. Knowing that will be important for calculating various things, such as how many degrees the freezing point will be depressed, when you dissolve so much salt in so much water.
1) Get the chemical formula to determine the number of each type of atom present in the compound. 2) Multiply the atomic weight (get it from the periodic table) of each element by the number of atoms of that element present your specific compound 3) Do the Sum in unit grams/mole NaCl (1x23 grams/mole Na) + (1x 35.5 grams/mole Cl) = 58.5 grams/mole NaCl
C = 12 grams/mole Cl = 35.45 grams/mole CCl4 = 12 + (35.45)x4 = 153.8 grams/mole 153.8 grams/mole / 6.022 x 1023 things/mole = 25.4 x 10-23 grams/thing where thing in this case would be a molecule of CCl4
Find the atomic or molecular weight of each and multiply it by the number of moles. atomic weight of carbon is 12 g/mole. atomic weight of chlorine is 35.45 g/mole molecular weight of fructose is 180.16 g/mole So just find the total grams. 10 moles Carbon * 12g/mole Carbon = 120 grams carbon 3 moles Chlorine * 35.45g/mole Chlorine = 106.35 grams Chlorine 1 mole Fructose * 180.16 g/mole Fructose = 180.16 grams Fructose So the answer is 1 mole of fructose.
I'll see if I can type it out for you.. 79g NaCl x (1 mol NaCl)/(58.44g NaCl) = 1.35 mol NaCl 1 mol NaCl = 58.44g (because Na is 22.99g and Cl is 35.45g)
One gram mole of common table salt, Sodium Chloride (NaCl) weighs 58.45 gm.