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How much does the pressure of a gas in a rigid vessel decrease when the temperature is decreased by 1 C?
Wiki User
∙ 14y ago
Ideal gas law: "PV = nRT"
rearranged: "P = (nR/V) * T"
therefore: "P is proportional to T if n,R,V are constant"
P = pressure
V = volume
n = amount of gas substance
R = gas constant
T = absolute temperature (in kelvin)
It is possible to say that if the temperature decrease by a certain percentage, the pressure would also decrease by the same percentage, because the two quantities are proportional. However, to know the absolute decrease in pressure due to an absolute decrease in temperature (ΔP = -?, given ΔT = -1°C), you would need to know more information, such as the initial values of P and T.
Wiki User
∙ 14y ago
Wiki User
∙ 9y agoThe decrease in the pressure of a certain gas in a rigid vessel depends on the type of gas inside the vessel. The ideal gas law can help in computing these values.
Wiki User
∙ 13y agoThe pressure decreases to the original pressure multiplied by the factor:
(the original Celsius temperature + 272.15) / (the original Celsius temperature + 273.15)
Wiki User
∙ 6y agoYes, it is true.
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A closed rigid pressure vessel contains 0.1 cum of liquid water and 99.9 cum of dry saturated steam at a pressure of 200 KP The vessel is heated until the pressure is 500 KP Find the final temperature?
divide it by the future number which is 0.99 which will equal 0.00000001
If water is contained in a closed vessel having an absolute pressure of 0.15 psia such as in the evaporator area of the absorption generator the water will boil at what temperature?
The temperature is 7 oC.
