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Without knowing the amperage capacity of the circuit the question is irrelevant. 4500 Watts at 240 volts would draw about 18.75 Amps. Calculating a little extra for safety would mean that you should use a 30 amp circuit. Perhaps that's not the question you were asking.
4500 watts is zero volts. To obtain a voltage from watts it has to be divided by an amperage.
No, the 20 amp (AWG #12) wire will be too small, you need to use AWG #10 wire. Even though 4500 watts is less that the 20 amp it can only be loaded to 80% by NEC rules which is 18.75 amps. The #12 wire would be overloaded so defiantly use AWG #10.
K refers to kilo, which is 1,000. So 4,500 ohms could be written as 4.5k ohms and pronounced 4.5 kilo ohms.
Answer for USA, Canada and countries running a 60 Hz supply service.You need a 30 amp 2-pole breaker and #10 AWG wire.As always, if you are in doubt about what to do, the best advice anyone should give you is to call a licensed electrician to advise what work is needed.Before you do any work yourself,on electrical circuits, equipment or appliances,always use a test meter to ensure the circuit is, in fact, de-energized.IF YOU ARE NOT ALREADY SURE YOU CAN DO THIS JOBSAFELY AND COMPETENTLYREFER THIS WORK TO QUALIFIED PROFESSIONALS.
4500 sq feet is a very large house. Big enough to comfortably fit a family of 5.
There are 43560 square feet in an acre. Therefore, rounded to three decimal places, 4500 square feet is equal to 4500/43560 = 0.103 acres.
There are 3 square feet in a square yard, so divide 4500 by 3.4500/3=1500 square yards
ranch style home - 1500 square foot with partial basement. What size generator would be needed?
It is 20250000.
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48600
4500 square meters is a much larger area.
500 x 9 = 4500 square feet
4500 sq ft ( 1 sq yard = 9 sq ft)
1 kanal = 4500 square feet = 500 square yards
No, There would not be a 4500 version of Silverado.