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Approx 2940 Joules.
How fast the energy is provided (power, in joules/second or watts) is irrelevant, as long as not too much energy gets radiated away. What you really need to know is how much energy (in joules) is needed.
The necessary heat is 9,22 joules.
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300 calories, which is equal to about 1255.2 joules
It had better be in joules. Watts and volts are not units of energy. yes, but how many as in ? joules/sec
Approx 2940 Joules.
How fast the energy is provided (power, in joules/second or watts) is irrelevant, as long as not too much energy gets radiated away. What you really need to know is how much energy (in joules) is needed.
A: Energy is measured in joules and kilojoules. One joule is the amount of energy needed to lift 100 grams to 1 kiliogram.
Voltage is electrical pressure and Joules is a power rating so other info is needed
Use the formula potential energy = mgh (mass x gravity x height), mass in kilograms, gravity about 9.8 (meters per square second), height in meters. Answer will be in Joules.
KE = 1/2mass * velocity squared some conversion needed 60 kilometer per hour (1000 meters/1 kg)(1 hr/3600 seconds) = 17 meter per second ================= KE = 1/2(1000 kilograms)(17 m/s)2 = 1.4 X 105 Joules ------------------------
I will use this formula. Some conversion will be required. ( I only know specific heat iron in J/gC ) q(Joules) = mass * specific heat * change in temperature Celsius 3 kilograms cast iron = 3000 grams q = (3000 g)(0.46 J/gC)(120 C - 30 C) = 124200 Joules (1 kilojoule/1000 joules) = 124.2 kilojoules of energy needed ===========================
The necessary heat is 9,22 joules.
You generally need a catalyst or a mechanism to convert the energy. For example to convert fuel (a mass) into thermal energy, oxidizer and a spark are needed.
That is the definition of a calorie. It is equal to 4.1868 joules.
1.94 x 10-18 Joules