Iodine sublimes - it does not melt
The necessary heat is 9,22 joules.
How fast the energy is provided (power, in joules/second or watts) is irrelevant, as long as not too much energy gets radiated away. What you really need to know is how much energy (in joules) is needed.
80 calories per gram (called the latent heat of fusion) 80 x 255.67 = 20453.6 calories
To calculate this, we can use the formula: energy needed = mass * heat of fusion. The heat of fusion for ice is 334 J/g. Thus, the energy needed to melt 5 grams of ice is 5 grams * 334 J/g = 1670 Joules.
The energy required to melt ice is known as the heat of fusion, which is about 334 joules per gram. Therefore, it would take approximately 3340 joules of energy to melt 10g of ice.
It takes approximately 64,000 Joules of energy to melt 1kg of gold. Therefore, to melt 2kg of gold, you would need around 128,000 Joules of energy.
The necessary heat is 9,22 joules.
To melt 1 gram of ice at 0°C, it requires 334 joules of energy. So for g grams of ice, the energy needed would be g multiplied by 334 joules.
It takes approximately 2.4 million joules of energy to melt 1 metric ton of iron.
800kj-----------Apex<('-'<)
The energy required to melt a substance is its heat of fusion. For Palladium (Pd), the heat of fusion is 16.74 kJ/mol. To calculate the energy needed to melt 4.24 grams of Pd, first convert to moles by dividing by the molar mass of Pd (106.42 g/mol), then multiply by the heat of fusion. This yields approximately 3.34 kJ of energy needed to melt 4.24 grams of Pd.
The energy needed to melt a substance is given by its heat of fusion. For L's, this value is typically around 334 J/g. So, to melt 25.4 grams of L's, you would need 25.4 grams x 334 J/g ≈ 8476 J of energy.
How fast the energy is provided (power, in joules/second or watts) is irrelevant, as long as not too much energy gets radiated away. What you really need to know is how much energy (in joules) is needed.
The energy required to melt a substance can be calculated using the heat of fusion value for that substance. The heat of fusion for palladium (Pd) is 16.74 kJ/mol. To convert grams to moles, divide the given mass by the molar mass of Pd (106.42 g/mol), then multiply by the heat of fusion value to find the energy needed to melt 4.24 grams of Pd.
80 calories per gram (called the latent heat of fusion) 80 x 255.67 = 20453.6 calories
To calculate this, we can use the formula: energy needed = mass * heat of fusion. The heat of fusion for ice is 334 J/g. Thus, the energy needed to melt 5 grams of ice is 5 grams * 334 J/g = 1670 Joules.
The energy required to melt ice is known as the heat of fusion, which is about 334 joules per gram. Therefore, it would take approximately 3340 joules of energy to melt 10g of ice.