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How much energy is needed to melt 25.4 grams of L's?
The energy needed to melt a substance is given by its heat of fusion. For L's, this value is typically around 334 J/g. So, to melt 25.4 grams of L's, you would need 25.4 grams x 334 J/g ≈ 8476 J of energy.
How much energy is needed to melt 2 kg of aluminum?
800kj-----------Apex<('-'<)
How much energy in kJ is needed to melt 183.3 g of water at 0 C?
The energy needed to melt ice is given by the formula Q = m * L_f, where Q is the energy required, m is the mass of water, and L_f is the heat of fusion of water (334 J/g). Converting 334 J/g to kJ/g gives 0.334 kJ/g. Multiplying these together, we find that 183.3 g of water will require 61.21 kJ of energy to melt at 0°C.
How much energy does it take to melt a 16.87 g ice cube?
It takes about 334 J/g to melt ice. So, to melt a 16.87 g ice cube, you would need about 5635.58 J of energy.
Energy required to melt a solid into a liquid?
The energy required to melt a solid into a liquid is known as the heat of fusion. This energy is needed to overcome the intermolecular forces holding the solid together and break down its crystal structure, allowing the particles to move freely in the liquid state. The amount of heat of fusion varies depending on the substance.
How much energy is needed to melt 25.4 grams of L's?
The energy needed to melt a substance is given by its heat of fusion. For L's, this value is typically around 334 J/g. So, to melt 25.4 grams of L's, you would need 25.4 grams x 334 J/g ≈ 8476 J of energy.
How much enjergy is needed to melt 4.24 grams of Pd?
The energy required to melt a substance is its heat of fusion. For Palladium (Pd), the heat of fusion is 16.74 kJ/mol. To calculate the energy needed to melt 4.24 grams of Pd, first convert to moles by dividing by the molar mass of Pd (106.42 g/mol), then multiply by the heat of fusion. This yields approximately 3.34 kJ of energy needed to melt 4.24 grams of Pd.
How much energy is needed to melt g of ice at 0 Celsius?
To melt 1 gram of ice at 0°C, it requires 334 joules of energy. So for g grams of ice, the energy needed would be g multiplied by 334 joules.
How much energy is needed to melt 5 grams of ice?
To calculate this, we can use the formula: energy needed = mass * heat of fusion. The heat of fusion for ice is 334 J/g. Thus, the energy needed to melt 5 grams of ice is 5 grams * 334 J/g = 1670 Joules.
How much energy is needed to melt 25.4grams of l2?
To calculate the energy needed to melt 25.4 grams of I2 (iodine), you can use the formula: energy = mass x heat of fusion. The heat of fusion for iodine is 15.52 kJ/mol. First, find the molar mass of I2 (253.8 g/mol) and then convert the mass to moles. Finally, multiply the moles by the heat of fusion to get the energy needed.
How much energy is needed to melt 255.67 grams of ice?
80 calories per gram (called the latent heat of fusion) 80 x 255.67 = 20453.6 calories
How much energy is needed to melt 2kg of gold?
It takes approximately 64,000 Joules of energy to melt 1kg of gold. Therefore, to melt 2kg of gold, you would need around 128,000 Joules of energy.
How much energy is needed to melt 0.25 moles of water?
The necessary heat is 9,22 joules.
How much energy is needed to melt 1 metric ton of iron?
It takes approximately 2.4 million joules of energy to melt 1 metric ton of iron.
How much energy is gained by 3 grams of ice when it changes to water?
The energy needed to change ice into water is called the heat of fusion. For ice, this value is around 334 joules per gram. So, for 3 grams of ice, the energy gained when it changes to water would be around 1002 joules (334 joules/gram * 3 grams).
How much energy is needed to melt 2 kg of aluminum?
800kj-----------Apex<('-'<)
How much ergy is required to melt 2 kg of gold?
The specific heat capacity of gold is 0.128 J/g°C, and the heat of fusion of gold is 63 J/g. To calculate the energy required to melt 2 kg of gold, you would first need to convert the mass to grams (2000 g). The energy required would be the sum of the energy needed to raise the temperature from the melting point to the melting point and the energy needed for the phase change.
