The energy required to melt a substance is its heat of fusion. For Palladium (Pd), the heat of fusion is 16.74 kJ/mol. To calculate the energy needed to melt 4.24 grams of Pd, first convert to moles by dividing by the molar mass of Pd (106.42 g/mol), then multiply by the heat of fusion. This yields approximately 3.34 kJ of energy needed to melt 4.24 grams of Pd.
To melt 1 gram of ice at 0°C, it requires 334 joules of energy. So for g grams of ice, the energy needed would be g multiplied by 334 joules.
It takes approximately 64,000 Joules of energy to melt 1kg of gold. Therefore, to melt 2kg of gold, you would need around 128,000 Joules of energy.
It takes approximately 2.4 million joules of energy to melt 1 metric ton of iron.
The energy needed to change ice into water is called the heat of fusion. For ice, this value is around 334 joules per gram. So, for 3 grams of ice, the energy gained when it changes to water would be around 1002 joules (334 joules/gram * 3 grams).
The specific heat capacity of gold is 0.128 J/g°C, and the heat of fusion of gold is 63 J/g. To calculate the energy required to melt 2 kg of gold, you would first need to convert the mass to grams (2000 g). The energy required would be the sum of the energy needed to raise the temperature from the melting point to the melting point and the energy needed for the phase change.
The energy needed to melt a substance is given by its heat of fusion. For L's, this value is typically around 334 J/g. So, to melt 25.4 grams of L's, you would need 25.4 grams x 334 J/g ≈ 8476 J of energy.
The energy required to melt a substance can be calculated using the heat of fusion value for that substance. The heat of fusion for palladium (Pd) is 16.74 kJ/mol. To convert grams to moles, divide the given mass by the molar mass of Pd (106.42 g/mol), then multiply by the heat of fusion value to find the energy needed to melt 4.24 grams of Pd.
To melt 1 gram of ice at 0°C, it requires 334 joules of energy. So for g grams of ice, the energy needed would be g multiplied by 334 joules.
80 calories per gram (called the latent heat of fusion) 80 x 255.67 = 20453.6 calories
To calculate this, we can use the formula: energy needed = mass * heat of fusion. The heat of fusion for ice is 334 J/g. Thus, the energy needed to melt 5 grams of ice is 5 grams * 334 J/g = 1670 Joules.
30 grams
To calculate the energy needed to melt 25.4 grams of I2 (iodine), you can use the formula: energy = mass x heat of fusion. The heat of fusion for iodine is 15.52 kJ/mol. First, find the molar mass of I2 (253.8 g/mol) and then convert the mass to moles. Finally, multiply the moles by the heat of fusion to get the energy needed.
This is a trick question because "I2" is the chemical symbol for MOLECULAR iodine (your question did not say melt Iodine, it said melt I2).Only gaseous iodine is composed of I2 molecules and as it is a gas it CAN NOT melt.
21 grams
about 10 grams a day should be fine
w much temparature is needed to melt CFC gases?
The necessary heat is 9,22 joules.