Want this question answered?
15480.80
Kilowatts is a unit of energy rate, while the temperature required to raise a specific volume of water by a specific amount of degrees is a unit of energy, not energy rate. The question cannot, therefore, be answered as stated. Please restate the question.
21 Kg = 2100 grams to rise the temperature of this amount of water by 2 degrees Celsius you need 2*2100 = 4200 calories or 17572.8 Joules.
The needed energy is 10 calories.
200
15480.80
4.1858 joules of energy will raise the temperature of 1 g of water by 1oC. Thus, 4.1858 * 955 * 80 = 319795.12 joules of energy is required to raise the temperature of 955 g of water by 1oC.
Kilowatts is a unit of energy rate, while the temperature required to raise a specific volume of water by a specific amount of degrees is a unit of energy, not energy rate. The question cannot, therefore, be answered as stated. Please restate the question.
A normal bath full of water. Sorry but this depends on units of energy that you are familiar with-. I will use caldepending where you are taug The enery required to raise the temperature of the a 1kg of water in a kettle from zero degrees to 100 is 100 kilocalories The bath contains more at least 20 kg of water, and the energy required to raise the temperature of that volume of water by 55 degrees is 20 X 55 = 1100 kcals
false its 1 degrees Celsius
100 degrees Celsius
The amount of heat required to increase the temperature of the substance to 1 degree greater than that of the initial temperature of the body!
200 BTU. I'm assuming your temperatures are in Fahrenheit, since all of your other measurements are in the Imperial system. A BTU is defined as the amount of energy required to raise the temperature of 1 pound water by 1 degree F, so the temperature is raised by 20 degrees, and 10 pounds of water: 20 x 10 = 200
The energy required to raise the temperature 1 degree Celsius of 1 gram of water (1 mL) is 1 calorie (=4.18 J). So for 1 kg, 1Kcal (= 4180 J = 4.18 KJ) is required. To raise it 60 degrees, just multiply by 60 and for 10 kg multiply by 10 again. That would make 2.508 MJ (= 2508000 J) Now this is not completely accurate. The energy required to raise the temperature of water differs at 20 degrees from that at 60 degrees. The difference is small (~0.05 J or something like that) but still present.
1 calorie is the energy required to raise 1 gram of water by 1 degree C. So it would take 5 calories to raise it by 5 degrees C.
21 Kg = 2100 grams to rise the temperature of this amount of water by 2 degrees Celsius you need 2*2100 = 4200 calories or 17572.8 Joules.
Because the evaporation of water carries heat away from the fire. Water has a high specific heat capacity. This is a measurement of the amount of energy required to cause a unit volume of a material to increase by a unit temperature. As such you must add a lot of energy to water to cause a small increase in temperature. For example to increase the temperature of 1 litre of water by 1 degrees C, you must add 4181.3 joules of energy.