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How much energy would be required to melt 500.g of ice at 0.00 degrees * C to water at 0.00 degrees * C ?
Joanna Flores
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Mossie Lueilwitz
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How much energy would be required to change 24.7 g of ice to liquid water?
8.25
How much energy would you use to raise temperature of kg of water by 2 degrees Celsius?
9.6 MJ
What is Water absorption coefficient formula?
If the water is not already at boiling temperature, then you will need equations 1 and 2. If the water is already at boiling temperature, you will only need equation 2.1. Q = m X C X ΔTThis equation is used to calculate how much energy is required to change the temperature of a given object, of given mass, by a given number of degrees.Q = the total amount of energy required, in joulesm = mass, in grams, of the object being heated (in this case, the water)C = the specific heat of the object (for water, 4.186)ΔT = the total change in temperature2. Q = 2.257 joules X mThe 2.257 in this equation is the heat of vaporization of water: that is, the amount of energy, required per gram of water, to boil water: 2.257 joules per gram. If you were using this equation for a different substance, you would have to look up its heat of vaporization, and substitute it in this equation.Q = the amount of energy required, in joulesm = mass, in grams, of the waterFor example, suppose you were asked to calculate how much energy it would take to boil 256 grams of water which is currently at 40 degrees Celsius. We know that the boiling temperature of water is 100 degrees Celsius; therefore the change in temperature, ΔT, is 100 - 40, which equals 60. Calculate as follows:Q = 256 grams X 4.186 X 60°CQ = 64296.96 joulesThis is how much energy it will take to raise the temperature of the water from 40°C to 100°C. Now calculate how much energy it will take to boil the water once it reaches 100°C:Q = 2.257 joules X 256 gramsQ = 577.792 joulesWe now take the energy required to raise the temperature of the water from 40°C to 100°C and add it to the energy required to boil the water:64296.96 joules + 577.792 joules = 64874.752 joulesConvert to kilojoules:64875.752 joules / 1000 = 64.875752 kilojoulesRound to 64.88 kilojoules.If you are required to express your answer in scientific notation, then express it as6.488 x 103 kilojoules.
How much heat is necessary to change 10 g of ice at 10C into water at 20C?
For 1 gram of water, you need 4.184 Joule to raise the T from 15 degrees Celsius to 16 degrees Celsius. The values are slightly different for other temperatures. So an estimation of the required energy would be 10 * 4.2 * 80. The 10 comes from 10 gram, the 4.2 from the energy required to heat 1 gram of water 1 degrees Celsius. The 80 comes from the starting temperature to the final temperature. The estimated answer is then 3360 J. For 1 gram of water, you need 4.184 Joule to raise the T from 15 degrees Celsius to 16 degrees Celsius. The values are slightly different for other temperatures. So an estimation of the required energy would be 10 * 4.2 * 80. The 10 comes from 10 gram, the 4.2 from the energy required to heat 1 gram of water 1 degrees Celsius. The 80 comes from the starting temperature to the final temperature. The estimated answer is then 3360 J.
Which would require a greater amount of heat water or iron?
To raise the temperature of both an equal amount, water would require more energy. In terms of the energy required to raise the temperature: iron = 0.45 joules / gram . kelvin water = 4.2 joules / gram . kelvin This is known as the specific heat capacity of a material
How many calories are required to raise the temperature of 1 g of water by 5 degrees C?
1 calorie is the energy required to raise 1 gram of water by 1 degree C. So it would take 5 calories to raise it by 5 degrees C.
How many btus does it take to raise half pound of water 1 degree?
One BTU is the energy required to raise one pound of water by one degrees. Therefore, your answer would be one half.
How much energy is needed to raise the maximum temperature of 10kg of water from 20 degrees Celsius to 80 degrees Celsius?
The energy required to raise the temperature 1 degree Celsius of 1 gram of water (1 mL) is 1 calorie (=4.18 J). So for 1 kg, 1Kcal (= 4180 J = 4.18 KJ) is required. To raise it 60 degrees, just multiply by 60 and for 10 kg multiply by 10 again. That would make 2.508 MJ (= 2508000 J) Now this is not completely accurate. The energy required to raise the temperature of water differs at 20 degrees from that at 60 degrees. The difference is small (~0.05 J or something like that) but still present.
What would happen if you increased the temperature in water?
the water molecules would begin to move faster (an increase in kinetic energy). if the water reached 100 degrees celcius (212 degrees Fahrenheit), it will boil.
How much heat energy would be required to bring a 15 kg block of ice from -20 degrees Celsius to steam at 120 degrees Celsius?
46389000 j
How much energy would be required to change 24.7 g of ice to liquid water?
8.25
What is an amount of water whose temperature would change by 15 degrees Celsius when it absorbs 2646 joules of heat energy?
The amount of water whose temperature would change by 15 degrees Celsius when it absorbs 2646 joules of heat energy is 42,2g H2O.
How much energy would you use to raise temperature of kg of water by 2 degrees Celsius?
9.6 MJ
What is the body temperature of a fish swimming in 60 degrees of water?
The body temperature of a fish swimming around in water that is 60 degrees would be 60 degrees also. This is because fish, unlike mammals, are coldblooded; they do not waste energy keeping their body temperature constant. Their body temperature would match that of the water around them.
How much energy is needed to boil water at 100 degrees?
The amount of energy to boil water depends on two things: the amount of water and the temperature of the water when you start.The more water water, the more energy it takes. The colder the water, the more energy it takes.Let say the water is at room temperature, or 20 °C. First, the water must be heated to 100 °C, which takes energy. The amount of energy is given by the specific heat of water, which is 4.186 Joule/gram °C. That means that requires 4.186 Joules of energy to heat 1 kilogram of water by 1 °C. So if you have 1 kilo grams of water at 20 °C, you have to add this much energy:= (4.18Joule/gram °C) (100g) (100 °C - 20 °C)= 334400 joules/°COf course, if you had more or less water, or it was colder or warmer, you would adjust this equation accordingly..
If you were at 0 degrees and 0 degrees would you be on land or in water?
in water
How many litters of water would required to fill a line pipe of 12mX24X10mm?
0.00000288 L at 4 degrees C, and 1 atmosphere
