How much energy is needed to boil water at 100 degrees?

Answer 1

The amount of energy to boil water depends on two things: the amount of water and the temperature of the water when you start.

The more water water, the more energy it takes. The colder the water, the more energy it takes.

Let say the water is at room temperature, or 20 °C. First, the water must be heated to 100 °C, which takes energy. The amount of energy is given by the specific heat of water, which is 4.186 Joule/gram °C. That means that requires 4.186 Joules of energy to heat 1 kilogram of water by 1 °C. So if you have 1 kilo grams of water at 20 °C, you have to add this much energy:

= (4.18Joule/gram °C) (100g) (100 °C - 20 °C)

= 334400 joules/°C

Of course, if you had more or less water, or it was colder or warmer, you would adjust this equation accordingly..

Answer 2

The energy required to boil water will depend upon the starting temperature of the water, your location above or below sea level, and the mass of water being boiled. This is because the boiling point of a substance is when its vapor pressure equals the pressure surrounding the liquid.

Answer 3

The answer depends on the volume of water and the current temperature.

It takes 1 calorie (~4.190 J) to raise 1 gram (1ml) of water 1 degree C.

To raise 1 gram of water from 0 degrees C (freezing) to 100 degrees C (boiling) it would take 100 calories (~419.0 joules).

Answer 4

Depends how much water and the temperature of the water.

To heat 1 mL of water by 1 degree C 1 cal of energy (4.184 Joules) is required. Assuming that the water is at 25 degrees C, to boil one litre (liter) of water you would require 75,000 cal or 313.8 kJ. Or 16.74 g of mars bar ;).

In terms of solar energy a 180 watt solar panel would take just under half an hour to gather enough energy to boil a litre of water from 25 degrees C (provided it's receiving maximum sunlight of course.

Answer 5

The specific heat capacity of water is 4.184 kJ.kg-1.K-1.

1 liter of water has a mass of 1kg. The boiling point of water is 100 0C. Delta T is thus 100-15 = 85 0C. 1 Kelvin is equivalent to 1 0C.

So 4.184 x 1 x 85 = 355.64 Kilojoules of energy.

Answer 6

Heat energy. However, it is easy to convert most types of energy into heat energy; for example, by vigorously stirring the pot, the mechanical energy will quickly be converted into heat energy.

Answer 7

Water doesn't boil until 216 degrees. So any amount of energy won't work at 100 degrees

Answer 8

It takes approximately 2260 Joules of energy to raise the temperature of 1 gram of water from 99 degrees Celsius to 100 degrees Celsius. This is known as the latent heat of vaporization.

Answer 9

From 22 degrees room temperature in a perfect world in a vacum, 3276kJ. Pure water From 22 degrees room temperature in a perfect world in a vacum, 3276kJ. Pure water

Answer 10

On the average, over the temperature range from zero to 100 Celsius,

it takes 1 calorie of energy to heat each milliliter of water you have

by 1 degree Celsius.