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1935 J
Q = 3 000 . 0,444 . ΔT (joules)ΔT is the difference of temperature.
To raise the temperature of both an equal amount, water would require more energy. In terms of the energy required to raise the temperature: iron = 0.45 joules / gram . kelvin water = 4.2 joules / gram . kelvin This is known as the specific heat capacity of a material
Iron naturally exists in solid state and heat is required for its liquifaction so liquid iron has high thermal energy.
(Explanation): remember to convert the 2kg to grams, then multiply in this equation Q=(2000)(0.45)(3) to get Q=2700J
538J
1935 J
The formula is: 0,108 x 3000 x (T1 -T2), in kilocalories.
Q = 3 000 . 0,444 . ΔT (joules)ΔT is the difference of temperature.
To raise the temperature of both an equal amount, water would require more energy. In terms of the energy required to raise the temperature: iron = 0.45 joules / gram . kelvin water = 4.2 joules / gram . kelvin This is known as the specific heat capacity of a material
I will use this formula. Some conversion will be required. ( I only know specific heat iron in J/gC ) q(Joules) = mass * specific heat * change in temperature Celsius 3 kilograms cast iron = 3000 grams q = (3000 g)(0.46 J/gC)(120 C - 30 C) = 124200 Joules (1 kilojoule/1000 joules) = 124.2 kilojoules of energy needed ===========================
Iron naturally exists in solid state and heat is required for its liquifaction so liquid iron has high thermal energy.
0.11cal/g degrees C
38 cal
(Explanation): remember to convert the 2kg to grams, then multiply in this equation Q=(2000)(0.45)(3) to get Q=2700J
The specific heat capacity of iron is 0,45 J/g.K.
That completely depends on the specific heat capacity of the substance of which the sample is composed, which you haven't identified. It will take a lot more heat energy to raise the temperature of 65 grams of water 35 degrees than it would take to do the same to 65 grams of iron or yogurt, e.g.