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How much energy is required to raise the temperature of kg of lead from 15 c to 15 c?
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∙ 9y ago
1935
Juliet Olson
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How much energy is required to raise the temperature of 3 kg of lead from 15 celsius to 20 celsius?
1935
How much energy is required to raise the temperature of 3 kg of lead from 15 to 20 degrees of celsius?
1935 J (apex)
How much energy is required to raise the temperature of 3 kg of lead from 15 degrees celsius to 20 degrees celsius?
1935 J (apex)
Does aluminum need more or less energy than lead to raise its temperature one degree?
more
The specific heat of lead is 128 kg degrees Celsius How much heat is needed to raise the temperature of a kg sample of lead by 10 degrees Celsius?
The relevant equation behind this problem is Q=m*c* ΔT Where Q is the energy that must be added to or taken from the system, m is the mass of the object, c is the objects specific heat, and ΔT is the change in temperature in Celsius or Kelvin. Plugging in the given values we get that Q=.015kg * 128J/(kg*C) * 10C=19.2J. Therefore, you need 19.2 joules of heat in order to raise the temperature of a .015kg sample of lead by 10 degrees Celsius.
How much energy is required to raise the temperature of kg of lead from 15 c to 20 c?
1935
How much energy is required to raise the temperature of 3 kg of lead from 15 celsius to 20 celsius?
1935
How much energy is required to raise the temperature of 3 kg of lead from 15 to 20 degrees of celsius?
1935 J (apex)
How much energy is required to raise the temperature of 3 kg of lead from 15 degrees celsius to 20 degrees celsius?
1935 J (apex)
Does aluminum need more or less energy than lead to raise its temperature one degree?
more
How much energy is required to raise the temperature of 3 kg of lead from 15 C to 20°C Use the table below and this equation: Q = mc ΔT.?
1935 JSource: Apex
How much energy is required to melt 1.5 of lead?
36.8 kj
Whats a calorie?
A calorie ('c') is a unit of measurement of the energy contained in food. One Calorie ('C', not to be confused with '°C' as in 'degrees Celsius') is equal to 1kcal, or 1,000 calories (or 4,184 joules). One calorie (1c, or 0.001kcal) ) is the amount of energy it takes to heat 1g of water by one degree Celsius (or by one degree Kelvin,°K); more specifically, from 14.5 °C to 15.5 °C (or 287.65 °K to 288.65 °K) as the thermal capacity of water is dependent upon temperature.Daily minimum energy requirements vary from person to person depending upon their sex, build, age, and level of physical activity. On average, the recommended daily intake for men is 2,500-3,300kcal per day, and for women, 1,500-2,500 per day.Most of that energy is required just to function (ie- heart beat, maintaining body temperature, etc.); this is referred to as your Basal Metabolic Rate. Failing to consume the required energy to cover your BMR plus any physical activity you participate in, will result in the increased consumption of energy stores in the body, leading to weight loss. Consuming more calories than you require will lead to weight gain as the body stores energy for later use in the form of fat.Continually failing to supply energy requirements will eventually lead to starvation. Once the body runs out of energy stores, it moves on to the muscles, bones, and ultimately, the internal organs, fighting to supply the required energy to keep you alive. Extreme or continual starvation will lead eventually to death.
Which one of the following materials would take the longest to raise the temperature water basalt iron or lead?
water
How much energy is required to raise the temperature of 3 kg of lead from 15C to 20C Use the table below and this equation Q mcT.?
1935 J on apex
What is the thermal energy of 50.0 of lead at room temperature 20?
1.9937*104 J
The specific heat of lead is 128 kg degrees Celsius How much heat is needed to raise the temperature of a kg sample of lead by 10 degrees Celsius?
The relevant equation behind this problem is Q=m*c* ΔT Where Q is the energy that must be added to or taken from the system, m is the mass of the object, c is the objects specific heat, and ΔT is the change in temperature in Celsius or Kelvin. Plugging in the given values we get that Q=.015kg * 128J/(kg*C) * 10C=19.2J. Therefore, you need 19.2 joules of heat in order to raise the temperature of a .015kg sample of lead by 10 degrees Celsius.
