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o calculate the amount of energy absorbed by 75 grams of iron when it is heated from 295K to 301K, we need to use the specific heat capacity of iron. The specific heat capacity of iron is 0.45 J/g*K. We can use the equation:

Q = m * c * delta T

Where Q is the energy absorbed, m is the mass of the substance (in this case, 75g of iron), c is the specific heat capacity of the substance (0.45 J/g*K for iron), and delta T is the change in temperature (301K - 295K = 6K). Plugging in the values, we get:

Q = 75g * 0.45 J/g*K * 6K

= 21 J

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So the 75 grams of iron will absorb 21 joules of energy as heat when it is heated from 295K to 301K.

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โˆ™ 1y ago
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โˆ™ 11y ago

2•10^2

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Q: How much energy would be absorbed as heat by 75g of iron when heat from 295k to 301k?
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How much energy would be absorb as heat by 75g of iron when heated from 295K to 301K?

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