Very simply 1g of ammonium thiocyanate and 100g (100ml) of water!
percent concentration = (mass of solute/volume of solution) X 100 To solve for mass of solute, mass of solute = (percent concentration X volume of solution)/100 So, mass of solute = (10% X 100mL)/100 = 10g
0.06% W/V = 0.06g / 100ml = 60mg/100ml = 0.6mg/ml
add 25ml more of solution x * 20 = 100 * 25 x = 25
dissolve 10g of TCA in 100ml distilled water.
A solution with the highest concentration of solute will contain the largest volume of solvent in 100mL. This means a dilute solution with a low amount of solute will have the highest volume of solvent remaining.
To prepare a 2% solution of ferric chloride in 100ml of water, you would need to add 2 grams of ferric chloride. This is calculated by multiplying the volume of the solution (100ml) by the desired concentration (2%) and converting it to grams.
It means that 100mL of solution has 75g of solute dissolved in it.
51% typically means 51% by volume. So if you have a 100ml bottle of 51% alcohol, you have 51ml of pure alcohol inside the bottle, diluted to a final solution volume of 100ml.
Simple equality. (100ml)(7%) = (500ml)(X%) = 1.4%
20 ml
A 10ml solution of 10 percent means that there are 10 grams of solute in 100ml of solution. Therefore, in 10ml of this solution, there would be 1 gram of the solute, as 10% of 10ml is 1ml of pure solute, which weighs 1 gram if the solute's density is 1 g/ml.
To make a 100ml 1M solution of Sodium Chloride, you would dissolve 5.85 grams of NaCl in enough water to make 100ml of solution. This molarity calculation is based on the molar mass of NaCl (58.44 g/mol).