Very simply 2g of ferric chloride and 100g (100ml) of water!
To make a 100ml 1M solution of Sodium Chloride, you would dissolve 5.85 grams of NaCl in enough water to make 100ml of solution. This molarity calculation is based on the molar mass of NaCl (58.44 g/mol).
percent concentration = (mass of solute/volume of solution) X 100 To solve for mass of solute, mass of solute = (percent concentration X volume of solution)/100 So, mass of solute = (10% X 100mL)/100 = 10g
A solution with the highest concentration of solute will contain the largest volume of solvent in 100mL. This means a dilute solution with a low amount of solute will have the highest volume of solvent remaining.
Measuring 3ml of Glacial Acetic Acid in a 100ml volumetric flask and diluting the same with water upto the 100ml mark will give exactly 3% solution of Acetic Acid containing 97% water...thats all, thank you
To prepare a 40% solution of potassium sodium tartrate, you would need to weigh out the appropriate amount of the salt and dissolve it in a specific volume of water to get the desired concentration. For example, to prepare 100mL of a 40% solution, you would mix 40g of potassium sodium tartrate with enough water to bring the final volume to 100mL.
To prepare ferric alum indicator, dissolve 5-10 grams of ferric ammonium sulfate in 100 ml of distilled water. This solution will serve as the indicator for chloride ions, turning yellow in the presence of chloride ions.
To make a 100ml 1M solution of Sodium Chloride, you would dissolve 5.85 grams of NaCl in enough water to make 100ml of solution. This molarity calculation is based on the molar mass of NaCl (58.44 g/mol).
percent concentration = (mass of solute/volume of solution) X 100 To solve for mass of solute, mass of solute = (percent concentration X volume of solution)/100 So, mass of solute = (10% X 100mL)/100 = 10g
0.06% W/V = 0.06g / 100ml = 60mg/100ml = 0.6mg/ml
2.5 g of Nacl is to be dissolve in 100ml of water gives 10ppm of Na solution.
Very simply 1g of ammonium thiocyanate and 100g (100ml) of water!
add 25ml more of solution x * 20 = 100 * 25 x = 25
Take 5 grams of calcium chloride and dissolve it in 100ml of solution to get a 5% solution of calcium chloride. The standard way to make a weight-volume solution is to take grams of the dry substance in 100ml of volume.
The needed mass is 0,0584 g.
dissolve 10g of TCA in 100ml distilled water.
A solution with the highest concentration of solute will contain the largest volume of solvent in 100mL. This means a dilute solution with a low amount of solute will have the highest volume of solvent remaining.
300 mg of orcinol in 100 ml of conc. HCl and 0.25 ml of ferric chloride solution (10g / 100ml ).