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Kilowatts is a unit of energy rate, while the temperature required to raise a specific volume of water by a specific amount of degrees is a unit of energy, not energy rate. The question cannot, therefore, be answered as stated. Please restate the question.
heat energy required to raise the temperature of ice by 29 celsius =specific heat capacity of ice * temperature change *mass of ice + to change 1kg of ice at 0 celsius to water at 0 celsius =specific latent of fusion of ice*mass of water + heat energy required to raise the temperature of water by 106 celsius =specific heat capacity of water * temperature change *mass of ice + to change 1kg of water at 106 celsius to steam at 106 celsius =specific latent of fusion of ice*mass of steam
To raise the temperature of both an equal amount, water would require more energy. In terms of the energy required to raise the temperature: iron = 0.45 joules / gram . kelvin water = 4.2 joules / gram . kelvin This is known as the specific heat capacity of a material
The equation Q=mcΔ t calculates the amount of energy for a body of mass to raise a unit temperature per unit mass. The specific heat capacity of water is 4.19 J/g°C which means that it takes 4.19 J to raise 1 g of water to 1°. The specific heat capacity also depends on what the surrounding temperature is. 4.19 J/g°C is the specific heat capacity at room temperature. Since temperature is the measurement of the average kinetic energy of the particles, the motion of particles in water affects the specific heat capacity which ultimately affects how much energy is needed to heat up water.
specific heat is the amount of thermal energy needed to raise the temperature of an object. for example, the water on the beach and the sand on the shore are absorbing the same amount of thermal energy from the sun but the water (which has high specific heat) is cold, and the sand (with low specific heat) is very hot.
It is harder to raise the temperature of water than it is to raise the temperature of a rock. It takes 1 calorie of energy to raise the temperature of 1 gram of water by 1 degree C, whereas it only takes 0.02 calorie to heat a gram of rock to that temperature.
Yes. The specific heat capacity of liquid water is 4.184 J/g•oC, and the specific heat capacity of steam is 2.010 J/g•oC.
It means that it takes more energy to raise the object's temperature by 1 degree than it does to increase the temperature of water by 1 degree..
These are not temperature numbers but specific heat numbers. They mean that it takes 4.184 Joules and 0.387 Joules respectively to raise water and copper of one gram by one degree celsius. So, as you can see, it takes a lot more heat to raise the temperature of water than it does of copper. Water has a very high specific heat.
Kilowatts is a unit of energy rate, while the temperature required to raise a specific volume of water by a specific amount of degrees is a unit of energy, not energy rate. The question cannot, therefore, be answered as stated. Please restate the question.
Water is something that will be affected if you raise the temperature. When cooking, you may need to raise the temperature of water to a boil, in order to cook food.
Water's high specific heat capacity helps to maintain body temperature. High specific heat capacity indicates a need for more energy to raise or lower the temperature of water. Sweat is another way that water helps maintain temperature. When sweat evaporates it draws in energy from the surroundings (the air and the body surfaces it is in contact with), effectively lowering the temperature.
This is the necessary energy to raise the temperature of 1 gram with 1 kelvin.
It is used to raise the temperature of the water.
The amount of heat required to increase the temperature of the substance to 1 degree greater than that of the initial temperature of the body!
Depends on how high you want to raise the gram of water ;).
heat energy required to raise the temperature of ice by 29 celsius =specific heat capacity of ice * temperature change *mass of ice + to change 1kg of ice at 0 celsius to water at 0 celsius =specific latent of fusion of ice*mass of water + heat energy required to raise the temperature of water by 106 celsius =specific heat capacity of water * temperature change *mass of ice + to change 1kg of water at 106 celsius to steam at 106 celsius =specific latent of fusion of ice*mass of steam