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q=(275)(11)(1.00)

q=3,025 cal

remember that the formula to find heat is:

q=m(DT)Cp

and remember that the specific heat of water is: 1.00 cal/(gxC)

you just replace values

hope this helps:)

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Q: How much heat is required to warm 25 g of water from 20deg cto 32deg c?
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