Want this question answered?
Well...if you drop a 0 for ten percent that would be 150. So half of that would be 5 percent which is 75.
It has very little to do with how much "weight" you lose, it's strictly how much fat you lose to drop bmi. You could lose 5 lbs and remain at the same bmi if all you lose is water and muscle. Dropping bmi takes a calculated and delibrate diet and exercise routine. If you are 142 lbs and are at 10 percent, then that means you have approx 14lbs of fat on your body. If your goal is to drop 3 points, then you simply figure out what 7 percent of 142 is....approx 10. So if you were to drop about 4 pounds of fat while keeping your overall weight at 142 you should find yourself at 7 percent.
The percent drop was never specified.
The national percentage of high school drop outs is 8.1 percent. Females have a 7 percent drop-out rate and males a 9.1 percent drop-out rate.
If it's a 50-amp panel designed for 100 percent full-time load at 120 volts, you would plug those numbers into a voltage-drop calculator and it will tell you. A #3 AWG copper conductor pair in conduit, overhead or direct burial will give you 85 Amps with only about 3.6 volts (3 percent) voltage drop. #4 AWG would give you 4 percent drop (at max current). #6 AWG would give 6 percent drop, but only 3.6 percent at 30 Amps.
antidiuretic hormone
EGGS
In for days the amount of medicine in his body will drop to exactly 0
30% of students drop out. 30% of students drop out.
17% of black people drop out
how to help build up your muscle
You don't. You have to build it up then drop whatever extra weight(Specifically body fat %) you gained while trying to retain the muscle. That is how you get definition.