The mass is 1,075 g.
The mass is 1,075 g.
The answer depends on 3240 WHAT: seconds, days, years?
79 grams <><><><><> AT = A0 2 (-T/H) AT = 250 2(-40/24.1) AT = ~79
Approx 100 atoms would remain.
After 42 days there would only be 1.00mg of Phosphorus-32 left in the organisms system
Your sample of phosphorous will literally half itself every 14 days. So after 14 days there is 12mg left. After 28 days, there is 6mg remaining.
Iodine 131 is radioactive and has a half life of about 8 days. After 32 days there would be approximately 5 milligrams remaining
12.5 g
8.1 days is, if half-life is 2.7 days, 3 half-lives. 12.5%, or 12.5 g, of 79198Au would remain after three half-lives.
If the half-life of a nuclide is 44.5 days, then 178 days is four half-lives. After four half-lives, 0.0625 (0.54) of the original nuclide remains. If 50g is the original mass, then the mass after 4 half-lives is 3.125g. AT = A0 2(-T/H) A178 = (50) 2(-44.5/178) A178 = 3.125
If a sample of radioactive material has a half-life of one week the original sample will have 50 percent of the original left at the end of the second week. The third week would be 25 percent of the sample. The fourth week would be 12.5 percent of the original sample.
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