0
What else can I help you with?
How many days until one-sixteenth of a 54.2 g sample of thorium-234 remains?
The half-life of thorium-234 is about 24 days. Therefore, it would take approximately 96 days for one-sixteenth of the original 54.2 g sample of thorium-234 to remain.
What is a half-line of a radioisotope if a 50-g sample becomes 25g after 18 days?
A half-life of a radioisotope is the time required for half of a sample to decay. In this case, a 50-g sample becoming 25 g after 18 days indicates that the half-life of the radioisotope is 18 days, as the sample has decreased to half its original amount in that time.
After how many days 1-4 of the original amount of gold 198 will remain?
After 4 days, only 1/16 of the original amount of gold (198/16 = 12.375) will remain.
The half-life of Au-198 is 2.7 days When there are 800 atoms of Au-198 in a sample a scientist starts a stopwatch The scientist stops the stopwatch at 8.1 days how many atoms of Au-198 remaining?
After 8.1 days, three half-lives have passed (8.1 days / 2.7 days = 3). With each half-life, the number of atoms is halved. Therefore, starting with 800 atoms, after three half-lives there would be 800 / 2 / 2 / 2 = 100 atoms remaining.
Iodine-131 decays to form xenon-131. The half-life of this reaction is 8.07 days. From a 200-g sample of iodine-131 how much of the sample is xenon-131 after 16.14 days?
After 16.14 days, which is two half-lives of iodine-131 (since 16.14 days / 8.07 days = 2), the amount of iodine-131 remaining would be (200 , \text{g} \times \left(\frac{1}{2}\right)^2 = 50 , \text{g}). Therefore, the amount of iodine-131 that has decayed to xenon-131 would be (200 , \text{g} - 50 , \text{g} = 150 , \text{g}). Thus, after 16.14 days, there would be 150 grams of xenon-131 formed.
How much of a 10-g sample of barium-131 would remain after 36 days?
The mass is 1,075 g.
What fraction of a radium sample will remain after 3240?
The answer depends on 3240 WHAT: seconds, days, years?
How many days until one-sixteenth of a 54.2 g sample of thorium-234 remains?
The half-life of thorium-234 is about 24 days. Therefore, it would take approximately 96 days for one-sixteenth of the original 54.2 g sample of thorium-234 to remain.
How much of a 100 g sample of thorium 234 will be unchanged after 48.2 days?
After 48,2 days the amount of Th-234 will be 25 g.
How many grams of radium-222 remain in a 12-gram sample after 76 seconds?
After 76 seconds, half of the radium-222 would have decayed (its half-life is about 3.8 days). Therefore, the quantity of radium-222 remaining in the 12-gram sample would be 6 grams.
The half life of Au198 is 2 7 days When there are 800 atoms of Au198 in a sample a scientist starts a stopwatch The scientist stops the stopwatch at 8 1 days there are atoms of Au198 rema?
At 8.1 days, 400 atoms of Au198 would remain in the sample. This is because after 8.1 days, two half-lives of Au198 have passed, reducing the initial 800 atoms to 400.
Thorium-234 has a half-life of 24.1 days. How much of a 100-g sample of thorium-234 will be unchanged after 48.2 days?
Thorium-234 has a half-life of 24.1 days. How much of a 100-g sample of thorium-234 will be unchanged after 48.2 days?
How many grams of a 250-g sample of thorium-234 would remain after 40 days had passed?
79 grams <><><><><> AT = A0 2 (-T/H) AT = 250 2(-40/24.1) AT = ~79
How much of an 80-milligram sample of Iodine-131 would be left after 32 days?
After 32 days, approximately 5 milligrams of the 80-milligram sample of Iodine-131 would be left. Iodine-131 has a half-life of about 8 days, so after each 8-day period, half of the remaining sample will decay.
Phosphorus32 a radioisotope used in the treatment of leukemiahas half-life of 14.0days.If a sample of8.00mg was administered to diagnose leukemia in a patienthow many mg would remain after 42day per?
After 42 days there would only be 1.00mg of Phosphorus-32 left in the organisms system
During an experiment a solution containing 24 mg of phosphorus 32 was preparedHow much of the isotope will remain after 28 days if its half-life is 14 days?
After 28 days, two half-lives would have passed (14 days x 2). This means the initial amount of phosphorus-32 would be reduced by three-quarters (1/2 x 1/2 = 1/4). Therefore, 6 mg (24 mg x 1/4) of phosphorus-32 will remain after 28 days.
A biologist noticed that the population of ladybugs in a sample doubled every 3 days If the initial population sample was 30 ladybugs what was the population of ladybugs at the end of 9 days?
After 9 days, the population of ladybugs would double every 3 days, so it would double 3 times. 2^3 = 8. Therefore, the population at the end of 9 days would be 30 ladybugs x 8 = 240 ladybugs.
