If your peice of concrete does not have beams I consider that flatwork. So in flatwork with 3/8 rebar (#3) on 16" centers, for the 15 foot side you will have 8 pieces x 15' long. On the 10' side you will need 12 pieces x 10'. (6 bars cut in half) In all you will need 14 #3 x 20'
A minimum of 1.3 cubic yards.
A 10-foot round slab at 4 inches requires 1 cubic yard.
I think you mean "How much area will 4 yards of concrete cover?". It depends on the slab thickness and whether or not anything significant is embedded (a lot of rebar, conduit, etc.). If working in feet, measure the width length and depth, multiply these numbers then divide the result by 27 to calculate the volume in cubic yards. A slab 9' 6" by 10' 4" by 6" thick translates to 9.5x10.3x.5 (48.93) /27 = 1.8 yards. Since you already have the volume, you will need to play with some of the dimensions to find something that works.
one yard of cement will make a 8 x 10 square foot slab at 4 inches thick, that's 80 sq. feet per yard of cement at 4 inches thick.
You'll need 1.23 Cubic Yards.
10-ft x 30-ft x 4-in = 100 cubic ft.That slab weighs 3.7 times as much as 1 "yard" of concrete. (rounded)
1.85 cubic yards.
10 cm = 0.1 meterThe volume of the slab is (6 x 8 x 0.1) = 4.8 cubic meters
15mm;density is 7851 kg/m3 unit wt = pi x (radius2) x 7851 kg/m3 = 1.387 kg/m
A minimum of 1.23 cubic yards at 4" thick.
Assuming you need a slab 25 feet x 32 feet x 4" you would need 10 yards of concrete. 25 x 32 x .33 / 27 = 9.7 cubic yards
The weight of 20mm diameter reinforcement bar is approximately 2.47 kg/m.