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Milli volt is one thousandth of a Volt and Milli amp is one thousandth of an Amp. Volt and Amp measure two different things and are not really comparable. Over simplified, here is how it works. Volt measures the 'pressure' that causes current to flow. Current flow is measured in Amps and depends on the how much resistance the 'pressure' has to overcome. Higher the resistance, lesser the current (Amp) for same pressure (Volt)
Usually a volt meter is placed across a component to measure the voltage drop across that component. Doing this places the volt meter resistance in parallel with that component's resistance, which will always lower the total resistance. Since the volt meter resistance is usually very large relative to the resistance of the element being measured, the total resistance does not change significantly. The formula for total resistance of two parallel elements is: Rtot = (R1*R2)/(R1+R2), as R1 (the volt meter) >> R2, Rtot ~= (R1*R2) / (R1) = R2 If a volt meter is placed into a circuit instead of around an element of that circuit, it will raise the resistance of the circuit, load the circuit with, and interrupt "normal" operation of the circuit (normal operation = how things would be without the meter in place). More importantly, the volt meter would then be measuring the voltage developped across itself (instead of an element of the circuit), which is not the point of this tool / this would be a misapplication of a volt meter.
The formulas you are looking for is I = E/R.
You can put less resistance (more load) on the battery with larger wires, but if you exceed a particular current output for a given duration, you will overheat the battery. To safely increase current output, use two batteries connected in parallel.
The unit of resistance is the 'Ohm'. A conductor through which a current of 1 ampere produces a voltage drop of 1 volt has a resistance of 1 ohm.
3 volt bulb gives the biggest resistance
resistance = volt / current . 440 volt across a parallel circuit means the same 440 volt across both resistance s. hence resistance r = volt / current . 440 / 20 amp = 27.5 ohms total resistance
The value of internal resistance of 1.5 volt battery is 0.5 ohms.
It depends on the resistance of the circuit, as V=IR, so I=V/R (V=Voltage, I=Current, R=Resistance)
Just use Ohms Law: V=IR, that is, voltage (in Volt) = current (in Ampere) x resistance (in Ohms).
The current output is governed by the load resistance of the circuit. The battery will try and supply as much current as needed up until the battery goes dead.
5 megohms
one volt applied across one ohm of resistance causes a current flow of one
A: Decreasing the current and/or the resistance
Milli volt is one thousandth of a Volt and Milli amp is one thousandth of an Amp. Volt and Amp measure two different things and are not really comparable. Over simplified, here is how it works. Volt measures the 'pressure' that causes current to flow. Current flow is measured in Amps and depends on the how much resistance the 'pressure' has to overcome. Higher the resistance, lesser the current (Amp) for same pressure (Volt)
Use a properly rated potentiometer.
There are several ways to convert a 240 volt input to a 1.5 volt output. If the 240 volt input is alternating current (AC), a simple transformer can reduce the 240 volts to 1.5 volts (AC). A properly configured resistor or impedance coil in series with the input and output would also do the job but a tansformer also serves to isolate the output from the input offering greater protection for the 1.5 volt device. You If 1.5 volts direct current (DC) is required, a rectifier circuit is needed after the 1.5 volt AC output. If the source is 240 volts (DC), A resistance circuit in series can reduce the output voltage. You can also use electronic circuitry to chop of the 1.5 volts.