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25 percent. Each successive polaroid with its axis parallel halves the amount of transmitted light. Therefore it would be 100%*(1/2)*(1/2) = 100%/4 = 25%
Unpolarized light has electromagnetic waves vibrating in all directions perpendicular to the direction of propagation. A polarizing filter only transmits light that is polarized along the same axis as the filter's axis. (Note that a polarizing filter also partially allows some orientations through that have some component of its axis along the same axis as the filter). The transmitted light thus constitutes half of the incident unpolarized light.Think of it like this: unpolarized light is like a rope vibrating up and down and a rope vibrating side to side. A polarizing filter is like "slots." If the slots are up and down, only up and down vibrations can get through. The other half- the side to side vibrations- are blocked.
50% - If the light incident on the first filter is unpolarized then 50% of the light will be transmitted (see other questions for a full explanation of why). Next, when this 50% arrives at the second filter, Malus' Law says that if the axes match up, then 100% will be transmitted. 100% of 50% is 50%. :-)
Butterworth filter works as an ideal low pass filter.Butterworth filter is best suited for the closed loop gain to be as close to 1 as possible within the passband.Roll-offs become steeper,they approach the ideal filter more closely.
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Advantage is that it has the most flat passband meaning that it is very good at simulating the passband of an ideal filter. The disadvantage is that it has a horrible stopband because it gradually goes to zero so some parts of the stopband are still passed. However, for an nth-order Butterworth Filter, as n increases, the closer it is to an ideal filter. However, it is highly impractical to build a ridiculously high order Butterworth filter.
Omnidirectional is the best brand for antennas because its ideal for high gain and wide coverage. They transmit or receive effectively in every direction.
If electricity is transmit at high current then this will requires heavy conductors,be it copper or aluminium. This will increase the cost of transmission. Also, the heating effects i.e the energy lost due to head will increase as well. Thus, it's never ideal to transmit electricity at high current.
Ideal filters having sharp cut-off & sharp cut-in for LPF & HPF but in practical filters there is some roll-off rate based on the order.
Drawback of the constant K type filter is that at the cut of frequency , its attenuation is a steady curve .. quick response is lacking in it an ideal filter should have a sharp response curve.
Bad ideal. Why would you want to ? It would just cause bad problems later.
It is not ideal to keep a jellyfish. The mechanical filtration could be any or none. The biological filtration is what does it all.